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kirill [66]
3 years ago
14

Can someone help me with this question.​

Mathematics
1 answer:
Alexxx [7]3 years ago
3 0

Answer:

I need to work it out I will coment when done

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Solve the equation to get x
Mariulka [41]

Answer:

the answer is

Step-by-step explanation:

x=1/2y+5---i

4x+3y=-20 ----ii

putting value of x in eqn Ii

4×(1/2×y+5)+3y=-20

2y+5+3y=-20

5y+5=-20

5y=-20-5

5y=-25

y=-25/5

y=-5

putting value in eqn I

x=1/2×-5+5

x=-5/2+5

x=5/2

4 0
2 years ago
What is the solution to the system for?
Sergeu [11.5K]

Answer:

x = 5 - 3y and y = - 7/3 + 5x/3

Step-by-step explanation:

uh -

I don't think that's what your looking for

5 0
3 years ago
What is the area of the trapezoid?
DiKsa [7]
The answer is actually choice B. To solve for the area of a trapezoid, you would do the formula a+b/2 h. 
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3 years ago
Can you please help me to solve this mathematical question:<br><br> (+1) - (-9) = ?
Rufina [12.5K]

Answer:

-8

this is the all answer but no steps

6 0
4 years ago
Read 2 more answers
What is Xavier’s available lot coverage?
slavikrds [6]

Answer:

<h2> <em><u>720</u></em><em><u>0</u></em></h2>

Step-by-step explanation:

<h3>At first:</h3>

<em><u>G</u></em><em><u>i</u></em><em><u>v</u></em><em><u>e</u></em><em><u>n</u></em><em><u>,</u></em>

Back of lot of the trapezoid = 175

Front of lot of the trapezoid = 185

Length of lot of the trapezoid = 100

<em><u>Therefore</u></em><em><u>,</u></em><em><u> </u></em>

Area of the trapezoid

=  \frac{a + b}{2} c

  • <em>[</em><em>On</em><em> </em><em>putting</em><em> </em><em>the</em><em> </em><em>values</em><em>]</em>

=  \frac{175 + 185}{2}  \times 100

  • <em>[</em><em>On</em><em> </em><em>Simplification</em><em>]</em>

= 360 × 50

  • <em>[</em><em>On multiplying</em><em>]</em>

= 18000

<em><u>Hence</u></em><em><u>,</u></em>

We got the <em>T</em><em>otal Area </em><em>as</em><em> </em><em>180</em><em>0</em><em>0</em><em>.</em>

<h3>Now:</h3>

<em><u>As</u></em><em><u> </u></em><em><u>per</u></em><em><u> </u></em><em><u>given</u></em><em><u> </u></em><em><u>equation</u></em><em><u>,</u></em>

  • \frac{40}{100}  =  \frac{x}{total \: area}
  • To find the value of x

<em><u>Solution</u></em><em><u> </u></em><em><u>,</u></em>

=  > \frac{40}{100}  =  \frac{x}{total \: area}

  • <em>[</em><em>On</em><em> </em><em>putting</em><em> </em><em>Total</em><em> </em><em>Area</em><em> </em><em>=</em><em> </em><em>180</em><em>0</em><em>0</em><em>]</em>

=  > \frac{40}{100}  =  \frac{x}{18000}

  • <em>[</em><em>On</em><em> </em><em>cross</em><em> </em><em>multiplication</em><em>]</em>

=> 40 × 18000 = 100 × x

  • <em>[</em><em>O</em><em>n</em><em> </em><em>Simplification</em><em> </em><em>]</em>

=> 720000 = 100x

  • <em>[</em><em>On</em><em> </em><em>dividing</em><em> </em><em>both</em><em> </em><em>sides</em><em> </em><em>with</em><em> </em><em>100</em><em>]</em>

=  >  \frac{720000}{100}  =  \frac{100x}{100}

  • <em>[</em><em>On</em><em> </em><em>Simplification</em><em> </em><em>]</em>

=> x = 7200

<em><u>Hence</u></em><em><u>,</u></em>

<em><u>Xavier's</u></em><em><u> </u></em><em><u>avaliable</u></em><em><u> </u></em><em><u>lot</u></em><em><u> </u></em><em><u>coverage</u></em><em><u> </u></em><em><u>(</u></em><em><u>x</u></em><em><u>)</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>720</u></em><em><u>0</u></em><em><u> </u></em><em><u>(</u></em><em><u>Ans</u></em><em><u>)</u></em>

7 0
3 years ago
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