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3 years ago

6

Graph the Systems of Equations below, then place a point indicating the solution to the system of equations.

2 answers:

77julia77 [94]3 years ago

8 0

Answer:

(4,-3)

Step-by-step explanation:

dimulka [17.4K]3 years ago

5 0

Answer:

Solution in image belo, make sure to put the lines on the right number's then out the point on (4, -3)

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What is the solution for the equation StartFraction 5 Over 3 b cubed minus 2 b squared minus 5 EndFraction = StartFraction 2 Ove

wolverine [178]

Answer:

The solutions are:

$b=0,\:b=4$

Step-by-step explanation:

Considering the expression

$\frac{5}{3b^3-2b^2-5}=\frac{2}{b^3-2}$

Solving the expression

$\frac{5}{3b^3-2b^2-5}=\frac{2}{b^3-2}$

$\mathrm{Apply\:fraction\:cross\:multiply:\:if\:}\frac{a}{b}=\frac{c}{d}\mathrm{\:then\:}a\cdot \:d=b\cdot \:c$

$5\left(b^3-2\right)=\left(3b^3-2b^2-5\right)\cdot \:2$

$5b^3-10=6b^3-4b^2-10$

$\mathrm{Switch\:sides}$

$6b^3-4b^2-10=5b^3-10$

$6b^3-4b^2-10+10=5b^3-10+10$

$6b^3-4b^2=5b^3$

$\mathrm{Subtract\:}5b^3\mathrm{\:from\:both\:sides}$

$6b^3-4b^2-5b^3=5b^3-5b^3$

$b^3-4b^2=0$

$Using\:the\:Zero\:Factor\:Principle:$ $if\:\mathrm ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)$

So,

$b=0,b-4=0$

$b=0,b=4$

Therefore, the solutions are:

$b=0,\:b=4$

4 0

3 years ago

Read 2 more answers

A survey of 46 college athletes found that 24 played volleyball, while 22 played basketball. a) If we pick one athlete survey pa

PSYCHO15rus [73]

Answer:

A) $\dfrac{11}{23}$

B) $\dfrac{88}{345}$

Step-by-step explanation:

A survey of 46 college athletes found that

24 played volleyball,
22 played basketball.

A) If we pick one athlete survey participant at random, the probability they play basketball is

$P_1=\dfrac{22}{46}=\dfrac{11}{23}$

B) If we pick 2 athletes at random (without replacement),

the probability we get one volleyball player is $\dfrac{24}{46}=\dfrac{12}{23};$
the probability we get another basketball player is $\dfrac{22}{45}$ (only 45 athletes left).

Thus, the probability we get one volleyball player and one basketball player is

$P_2=\dfrac{12}{23}\cdot \dfrac{22}{45}=\dfrac{88}{345}$

5 0

3 years ago

A tourist purchases a car in england and ships it home to the united states. the car sticker advertised that the car's fuel cons

Valentin [98]

<u>Solution-</u>

Fuel consumption rate = 40 miles per UK gallon (As the car is manufactured in UK)

1 UK gallon = 4.5459631 lit

1 US gallon = 3.7853060 lit

$\therefore \frac{1 \ UK \ gallon}{1 \ US \ gallon} = \frac{4.5459631}{3.7853060} = 1.2009499$

$\Rightarrow 1 \ UK \ gallon = 1.2009499 \ US \ gallon$

As the fuel consumption rate = 40 miles per gallon

⇒ You need 1 UK gallon of fuel to go 40 miles

⇒ You need 1.2009499 US gallon of fuel to go 40 miles

Or you can say that, to go 40 miles you need 1.2009499 US gallon of fuel

⇒ To go 1 mile you will need $\frac{1.2009499}{40} = 0.0300237$

⇒ To go 738 miles you will need 0.0300237×738 = 22.1574906 US gallon of fuel

∴ 22.1574906 gallon of fuel is actually required.

∴ But, what she thinks will require is $\frac{738}{40} = 18.45 gallons$ (As she calculated using UK gallons)

6 0

2 years ago

Help me find the answer <br>Tan 0 and Cot O

vesna_86 [32]

Answer:

Step-by-step explanation:

we can say the angle is also +45° going in the clock wise direction. so take Tan(45)= 1

Cot(45) = 1

b/c Tan(45) = Sin(45) /Cos(45) = ( $\sqrt{2}$ /2) / ( $\sqrt{2}$ /2) ofc that's just 1

b/c Cot(45) = Cos(45) / Sin(45) , which is the same as above 1

3 0

3 years ago

Please answer this question

makvit [3.9K]

Step-by-step explanation:

Using the properties of logarithms, the left side of the equation becomes

$\log{3x^3} - \log{x^2} = \log{3x}$

while the right hand side becomes

$\log{27} - \log{x} = \log{\frac{27}{x}}$

so we end up with

$3x^2 =27 \Rightarrow x = 3$

4 0

2 years ago