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Natali5045456 [20]
3 years ago
8

Felix can have 1 fish for every 4,000 mm of water in his fish tank. his fish tank holds 180 l. how many fish can he have in his

tank?
Mathematics
1 answer:
Alenkasestr [34]3 years ago
3 0
45 fish

1 L = 1,000 mL
180(1,000) = 180,000
180 L = 180,000 mL
180,000/4,000 = 45

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3x + 4 = 8x – 11 does anyone know how to do this ​
Nataly [62]

Answer:

x = 3

Step-by-step explanation:

Subtract 8x from both sides.

3x+4−8x=8x−11−8x

−5x+4=−11

Subtract 4 from both sides.

−5x+4−4=−11−4

−5x=−15

Divide both sides by -5.

−5x

−5

=

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−5

x=3

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Can you guys name the property please.
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Answer:

I think A. Reflexive Property but if I am wrong, I am so sorry

Step-by-step explanation:

because 6 + 1 is is not subtracting or multiplying

Hope this helps

3 0
2 years ago
Colin’s piano lesson is 45 minutes, or Three-fourths of an hour, long. If he practices 6 different songs and spends an equal amo
NikAS [45]

Answer:

<em>Colin spends 1/8 of an hour practicing each song</em>

Step-by-step explanation:

Colin's piano lesson is 3/4 of an hour, long.

In that period, he practices 6 different songs, spending an equal amount of time on each one.

This means that each song gets the sixth part of the lesson duration. The fraction that expresses that amount is:

\displaystyle \frac{\frac{3}{4}}{6}=\frac{3}{24}=\frac{1}{8}

Colin spends 1/8 of an hour practicing each song

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3 years ago
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Find the diameter of the circle (x-4)2 + (y + 6)2 = 16.<br> A)2<br> B)4<br> C)8<br> D)16
Rzqust [24]

Answer:

The answer is C ) 8

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So times that by 2 gives you 8

Step-by-step explanation:

6 0
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How many ml of a 20% acid mixture and a 80% acid mixture should be mixed to get 120ml of a 35% acid mixture?
shutvik [7]

Answer:

Volume of Mixture A =90 ml

Volume of Mixture B =30 ml

Step-by-step explanation:

Let say, Mixture A + Mixture B = Mixture C

Volume of Mixture A is x

Volume of Mixture B is y

So, Volume of Mixture C is x+y = 120 ml

Now, Acid contain in Mixture A is 20% =0.2x

Acid contain in Mixture B is 80% =0.8y

Also, Acid contain in Mixture C is 35% =(0.35)(x+y) = 0.35×120=42

Now, we know that,

Acid contain of Mixture A + Acid contain of Mixture B=Acid contain of Mixture C

∴ 0.2x+0.8y=42

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2x+8y=420 and x+y = 120

Solving above equation...

∴ x=120-y

Replacing x value in 2x+8y=420

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∴ y=30

Replacing y value in any equation

∴ x=120-y=120-30=90

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Thus,

Volume of Mixture A is x=90 ml

Volume of Mixture B is y=30 ml

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