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Alborosie
3 years ago
13

At King Kong High School, the average weight of senior boys is 168 lbs. with a standard deviation of 7 lbs. The average weight f

or senior girls is 117 lbs. with a standard deviation of 5 lbs. Suppose a new distribution is created by adding the boys' weights and the girls' weights together. Assuming that the weights for boys and girls are independent, which of the following is true?
I. The mean of this new distribution is 168 + 117.

II. The standard deviation of this new distribution is 5+ 7.

III. The variance of this new distribution is 52 + 72

A) I only

B) II only

C) I and II only

D) I and III only

E) I, II, and III
Mathematics
1 answer:
finlep [7]3 years ago
8 0

Answer:

1 and 2 only

Step-by-step explanation:

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Answer:

A:

The perimeter of the parking lot is 302 yards.

The area of the parking lot is 5,544 yards squared.

B: Perimeter

C: Area

Step-by-step explanation:

A:

To find the perimeter of the parking lot, we add all the sides up. 2L + 2W = Perimeter.

2(63) + 2 (88) = 302

To find the area, we multiply the length by the width. 63 × 88 = 5,544.

B: We need to know the amount of chain needed to surround the parking lot. In other words, we need to line the perimeter with a chain.

C: We would be paving the entire area of the parking lot.

Hope this helps,

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6 0
4 years ago
Help me please this test is very important !
Lilit [14]

Answer:

d

Step-by-step explanation:

5>2n+11

5-11>2n

-6>2n

-6/2>n

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6 0
3 years ago
Grace, Chelsea, and Roan are simplifying the same polynomial expression. Which
Alexus [3.1K]

Answer:

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3(2 - x) - 2(6x - 8)

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6 0
3 years ago
0.45m-9=0.9m, what is the least power of ten you could multiply by to write an equivalent equation with integer coefficients?
tia_tia [17]

Answer:

m = -20

Step-by-step explanation:

Step 1 :

9

Simplify ——

10

Equation at the end of step 1 :

45 9

((——— • m) - 9) - (—— • m) = 0

100 10

Step 2 :

9

Simplify ——

20

Equation at the end of step 2 :

9 9m

((—— • m) - 9) - —— = 0

20 10

Step 3 :

Rewriting the whole as an Equivalent Fraction :

3.1 Subtracting a whole from a fraction

Rewrite the whole as a fraction using 20 as the denominator :

9 9 • 20

9 = — = ——————

1 20

Equivalent fraction : The fraction thus generated looks different but has the same value as the whole

Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator

Adding fractions that have a common denominator :

3.2 Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

9m - (9 • 20) 9m - 180

————————————— = ————————

20 20

Equation at the end of step 3 :

(9m - 180) 9m

—————————— - —— = 0

20 10

Step 4 :

Step 5 :

Pulling out like terms :

5.1 Pull out like factors :

9m - 180 = 9 • (m - 20)

Calculating the Least Common Multiple :

5.2 Find the Least Common Multiple

The left denominator is : 20

The right denominator is : 10

Number of times each prime factor

appears in the factorization of:

Prime

Factor Left

Denominator Right

Denominator L.C.M = Max

{Left,Right}

2 2 1 2

5 1 1 1

Product of all

Prime Factors 20 10 20

Least Common Multiple:

20

Calculating Multipliers :

5.3 Calculate multipliers for the two fractions

Denote the Least Common Multiple by L.C.M

Denote the Left Multiplier by Left_M

Denote the Right Multiplier by Right_M

Denote the Left Deniminator by L_Deno

Denote the Right Multiplier by R_Deno

Left_M = L.C.M / L_Deno = 1

Right_M = L.C.M / R_Deno = 2

Making Equivalent Fractions :

5.4 Rewrite the two fractions into equivalent fractions

Two fractions are called equivalent if they have the same numeric value.

For example : 1/2 and 2/4 are equivalent, y/(y+1)2 and (y2+y)/(y+1)3 are equivalent as well.

To calculate equivalent fraction , multiply the Numerator of each fraction, by its respective Multiplier.

L. Mult. • L. Num. 9 • (m-20)

—————————————————— = ——————————

L.C.M 20

R. Mult. • R. Num. 9m • 2

—————————————————— = ——————

L.C.M 20

Adding fractions that have a common denominator :

5.5 Adding up the two equivalent fractions

9 • (m-20) - (9m • 2) -9m - 180

————————————————————— = —————————

20 20

Step 6 :

Pulling out like terms :

6.1 Pull out like factors :

-9m - 180 = -9 • (m + 20)

Equation at the end of step 6 :

-9 • (m + 20)

————————————— = 0

20

Step 7 :

When a fraction equals zero :

7.1 When a fraction equals zero ...

Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.

Now,to get rid of the denominator, Tiger multiplys both sides of the equation by the denominator.

Here's how:

-9•(m+20)

————————— • 20 = 0 • 20

20

Now, on the left hand side, the 20 cancels out the denominator, while, on the right hand side, zero times anything is still zero.

The equation now takes the shape :

-9 • (m+20) = 0

Equations which are never true :

7.2 Solve : -9 = 0

This equation has no solution.

A a non-zero constant never equals zero.

Solving a Single Variable Equation :

7.3 Solve : m+20 = 0

Subtract 20 from both sides of the equation :

m = -20

One solution was found :

m = -20

6 0
3 years ago
On the school football team, 2/12 of the students are first graders. In simplest form, what fraction of the students on the scho
almond37 [142]
I/6 you would just divide it
7 0
3 years ago
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