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3 years ago

Please help me ASAP

Mathematics

1 answer:

Lelechka [254]3 years ago

7 0

Answer:

I think 12 is the answer

Step-by-step explanation:

In ∆ QOP

R and S is the midpoint of OQ and PQ

and RS is parallel to OP

Therefore , By BPT

∆QRS is similar to ∆ QOP

let QS length be 1 unit

therefore , QP is 2 unit ( because QS is half of QP )

RS / OP = QS / QP

18-4x / -9+7x = 1 / 2

after cross multiplying

36-8x = -9+7x

36+9 = 7x+8x

45 = 15x

x=3

we have OP length = -9+7x

put the value of x in above equation

-9+7×3

-9+21

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Read 2 more answers

HELP ME PLEASEE

Nina [5.8K]

Answers:

x = -8/5 or x = 8/5

Sum of the first ten terms where all terms are positive = 4092

========================================================

Explanation:

r = common ratio

first term = 4
second term = (first term)*(common ratio) = 4r
third term = (second term)*(common ratio) = (4r)*r = 4r^2

The first three terms are: 4, 4r, 4r^2

We're given that the sequence is: 4, 5x, 16

Therefore, we have these two equations

5x = 4r
4r^2 = 16

Solve the second equation for r and you should find that r = -2 or r = 2 are the only possible solutions. If r = -2, then 5x = 4r solves to x = -8/5. If r = 2, then 5x = 4r solves to x = 8/5.

-----------------

To find the sum of the first n terms, we use this geometric series formula

Sn = a*(1 - r^n)/(1 - r)

We have

a = 4 = first term
r = 2, since we want all the terms to be positive
n = 10 = number of terms to sum up

So,

Sn = a*(1 - r^n)/(1 - r)

S10 = 4*(1 - 2^10)/(1 - 2)

S10 = 4*(1 - 1024)/(-1)

S10 = 4*(-1023)/(-1)

S10 = 4092

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3 years ago

Roberto rowed 20 miles downstream in 2.5 hours. The trip back, however, took him 5 hours. Find the rate that Roberto rows in sti

almond37 [142]

Answer:

Roberto's speed in still water is 6 miles/hour and the river speed is 2 miles/hour

Step-by-step explanation:

Relative Speed

When a body is moving at a constant speed v, the distance traveled in a time t is:

$d=v.t$

When Roberto rows downstream, his speed in still water is added to the speed of the water, making it easier to travel the required distance.

When Roberto rows upstream, his speed in still water is affected by the speed of the water, both are subtracted and the required distance is covered in more time.

Let's call

x = Roberto's rowing speed in still water

y = Speed of the river current

The speed when rowing downstream is x+y, thus the distance traveled is

$d=(x+y).t_1$