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Answer:
<em>a)C4H5N2O</em>
<em>b)C12H22O11</em>
<em>c)HO2</em>
<em>d)CH2O</em>
<em>e)C3H4O3</em>
Explan ation:
To obtain th e empirical formul a from the molecular for mula you have to divide the subscripts by the largest whole number you can, that provide you a whole number for each one subscripts:
Answer:
Carbon-12: with 6 protons and 6 neutrons and an atomic mass of 12.
Explanation:
<span>They have chloroplasts and use light energy to make more food. I think might be wrong </span>
First, let us find the corresponding amount of moles H₂ assuming ideal gas behavior.
PV = nRT
Solving for n,
n = PV/RT
n = (6.46 atm)(0.579 L)/(0.0821 L-atm/mol-K)(45 + 273 K)
n = 0.143 mol H₂
The stoichiometric calculations is as follows (MW for XeF₆ = 245.28 g/mol)
Mass XeF₆ = (0.143 mol H₂)(1 mol XeF₆/3 mol H₂)(245.28 g/mol) = <em>11.69 g</em>
