<u>Answer:</u> The mass of methylene blue that must be weighed is 
<u>Explanation:</u>
To calculate the mass of solute, we use the equation used to calculate the molarity of solution:

We are given:
Molarity of solution = 
Molar mass of methylene blue = 319.85 g/mol
Volume of solution = 100.0 mL
Putting values in above equation, we get:

Hence, the mass of methylene blue that must be weighed is 
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Answer:
8.4) 27.1 cm³
8.5) 0.217 mol/dm³
Explanation:
Please see attached picture for full solution.
8.4) Since the results from titrations 3-5 are within 0.10cm³ from each other, these 3 results are concordant.
8.5) Find mol of sulfuric acid to find mol of NaOH using mole ratio. Equation has already been balanced for you, so mole ratio of NaOH to H2S04 is 2:1. To find concentration of NaOH, divide the number of moles by the volume in dm³ since the units for concentration is mol/dm³, which you can think of as the number of moles of NaOH in a dm³ of solution.
1 dm³ = 1000cm³
Thus, 1cm³= 1/1000 dm³
Answer:
XCl2(aq) + 2 AgNO3(aq) = 2 AgCl(s) + X(NO3)2(aq)