Answer:
Coordinate of E:(-2,3) Coordinate of G: (2.5,1.5)
Parallel: slopes both = -1/3
1/2 segment: EG length= 3 BC length=6: This is the only one I'm not sure about.
I will show the work for both the problems down below.
Step-by-step explanation:
Finding coordinates:
1+(-5)/2=-2 5+1/2=3
(-2,3)
1+4/2= 2.5 5+(-2)/2= 1.5
(2.5,1.5)
Show work verifying the EG and BC are parallel:
You can do this by finding the slope
Slop formula (y2-y1)/(x2-x1)
(1.5-3)/(2.5-(-2))
Then simplify
-1.5/2/5= -1/3 which i your slope. You use the same formula and follow thee same steps for the points of BC and both will come up as -1/4 meaning they are parallel.
Show work verifying that EG and BC are parallel:
Use distance formula to find how long each line is
√(x2-x1)^2+(y2-y1)^2
√(2.5-(-2)^2)+(1.5-3)^2
Simplify
√4.5+(1.5)=3
Do the same thing with BC and you will get 6
On the y-axis, the graph crosses 0 because proportional relationships start at the origin, or (0,0). The line will be straight because a proportional relationship has a constant, meaning it will have a constant rate of change, therefore, it is linear.
With
we have
so 
has one eigenvalue, 
, with multiplicity 3.
In order for to not be defective, we need the dimension of the eigenspace to match the multiplicity of the repeated eigenvalue 2. But 
has nullspace of dimension 2, since
That is, we can only obtain 2 eigenvectors,
and there is no other. We needed 3 in order to complete the basis of eigenvectors.
Answer:
-4
Step-by-step explanation:
Answer:
8
Step-by-step explanation:
