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2 years ago

6+6+75millllllliioooon

Mathematics

1 answer:

Mice21 [21]2 years ago

6 0

Answer:

75,000,012

Step-by-step explanation:

enjoy, i guess

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Which equation represents a linear function? Equation 1: y = 2x2 + 1 Equation 2: y = 8x + 1 Equation 3: y = 5x3 – 1 Equation 4:

zloy xaker [14]

Equation 2 is the only linear one due to the fact that there is no exponent on the x or y values.

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3 years ago

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Dividing mixed numbers

Mars2501 [29]

$\frac{9}{14}$

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3 years ago

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Find the equation of the sphere if one of its diameters has endpoints (4, 2, -9) and (6, 6, -3) which has been normalized so tha

Pavel [41]

Answer:

$(x - 5)^2 + (y - 4)^2 + (z - 6)^2 = 14$ .

(Expand to obtain an equivalent expression for the sphere: $x^2 - 10\,x + y^2 - 8\, y + z^2 - 12\, z + 63 = 0$ )

Step-by-step explanation:

Apply the Pythagorean Theorem to find the distance between these two endpoints:

$\begin{aligned}&\text{Distance}\cr &= \sqrt{\left(x_2 - x_1\right)^2 + \left(y_2 - y_1\right)^2 + \left(z_2 - z_1\right)^2} \cr &= \sqrt{(6 - 4)^2 + (6 - 2)^2 + ((-3) - (-9))^2 \cr &= \sqrt{56}}\end{aligned}$ .

Since the two endpoints form a diameter of the sphere, the distance between them would be equal to the diameter of the sphere. The radius of a sphere is one-half of its diameter. In this case, that would be equal to:

$\begin{aligned} r &= \frac{1}{2} \, \sqrt{56} \cr &= \sqrt{\left(\frac{1}{2}\right)^2 \times 56} \cr &= \sqrt{\frac{1}{4} \times 56} \cr &= \sqrt{14} \end{aligned}$ .

In a sphere, the midpoint of every diameter would be the center of the sphere. Each component of the midpoint of a segment (such as the diameter in this question) is equal to the arithmetic mean of that component of the two endpoints. In other words, the midpoint of a segment between $\left(x_1, \, y_1, \, z_1\right)$ and $\left(x_2, \, y_2, \, z_2\right)$ would be:

$\displaystyle \left(\frac{x_1 + x_2}{2},\, \frac{y_1 + y_2}{2}, \, \frac{z_1 + z_2}{2}\right)$ .

In this case, the midpoint of the diameter, which is the same as the center of the sphere, would be at:

$\begin{aligned}&\left(\frac{x_1 + x_2}{2},\, \frac{y_1 + y_2}{2}, \, \frac{z_1 + z_2}{2}\right) \cr &= \left(\frac{4 + 6}{2},\, \frac{2 + 6}{2}, \, \frac{(-9) + (-3)}{2}\right) \cr &= (5,\, 4\, -6)\end{aligned}$ .

The equation for a sphere of radius $r$ and center $\left(x_0,\, y_0,\, z_0\right)$ would be:

$\left(x - x_0\right)^2 + \left(y - y_0\right)^2 + \left(z - z_0\right)^2 = r^2$ .

In this case, the equation would be:

$\left(x - 5\right)^2 + \left(y - 4\right)^2 + \left(z - (-6)\right)^2 = \left(\sqrt{56}\right)^2$ .

Simplify to obtain:

$\left(x - 5\right)^2 + \left(y - 4\right)^2 + \left(z + 6\right)^2 = 56$ .

Expand the squares and simplify to obtain:

$x^2 - 10\,x + y^2 - 8\, y + z^2 - 12\, z + 63 = 0$ .

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2 years ago

Convert 2000 Swiss francs to Dutch guilders

Shtirlitz [24]

Answer:

2000 swiss francs equals 3920 Dutch Guilders!

Step-by-step explanation:

One Swiss Franc equals 1.96 Dutch Guilders. Having said this, we can come up with the following equation:

D = 1.96S

Where 'S' represents the swiss francs and 'D' the Dutch Guilders. Now, to convert 2000 Swiss francs, we just need to plug the value into the equation:

D = 1.96(2000) = 3920

So, 2000 swiss francs equals 3920 Dutch Guilders!

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3 years ago

if 500 is deposited into an account earning 6 percent simple interest what is the future value in 6 years how do you work it put

djverab [1.8K]

$\bf \qquad \textit{Simple Interest Earned Amount}\\\\
A=P(1+rt)\qquad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to& \$500\\
r=rate\to 6\%\to \frac{6}{100}\to &0.06\\
t=years\to &6
\end{cases}
\\\\\\
A=500(1+0.06\cdot 6)$

4 0

3 years ago