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Lana71 [14]
3 years ago
9

Please answer. I will be picking the brainiest answer as well!

Chemistry
1 answer:
Dima020 [189]3 years ago
7 0
I think it’s Diagram 2. correct me if i’m wrong
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you are heating a solution and recording its temperature every 2 min during an experiment. which is your independent variable an
Zepler [3.9K]
An independent variable is the variable you are changing in order to measure the dependent variable, which is what you are measuring.

In this example, the

independent variable: chemicals in solution
dependent variable: temperature of solution
7 0
3 years ago
80 protons, 119 neutron
g100num [7]
Mercury-199 is composed of 80 protons, 119 neutrons, and 80 electrons.
4 0
2 years ago
Black coffee has a pH of around 5. Since pH and pOH have an inverse relationship, black coffee has a pOH of ___.
Anon25 [30]

Answer:

pOH = 9.

Explanation:

The inverse relationship between the pH and pOH of any given solution can be written as:

pH = 14 - pOH

Or conversely:

pOH = 14 - pH

With the above information in mind we can <u>use the given pH to calculate the pOH</u>:

pOH = 14 - pH

pOH = 14 - 5

pOH = 9

Thus, black coffee has a pOH of 9.

5 0
3 years ago
How many grams of silver oxide are needed to react with 7.9 g of hydrochloric acid produce silver chloide and water?
Anastaziya [24]

Answer:

25.11 g.

Explanation:

  • It is clear from the balanced equation:

<em>Ag₂O + 2HCl → 2AgCl + H₂O.</em>

<em></em>

that 1.0  mole of Ag₂O reacts with 2.0 moles of HCl to produce 2.0 mole of AgCl and 1.0 moles of H₂O.

  • 7.8 g of HCl reacts with excess Ag₂O. To calculate the no. of grams of Ag₂O that reacted, we should calculate the no. of moles of HCl:

<em>no. of moles of HCl = mass/atomic mass</em> = (7.9 g)/(36.46 g/mol) = <em>0.2167 mol.</em>

  • From the balanced equation; every 1.0 mol of Ag₂O reacts with 2 moles of HCl.

∴ 0.2167 mol of HCl will react with (0.2617 mol / 2 = 0.1083 mol) of Ag₂O.

<em>∴ The mass of reacted Ag₂O = no. of moles x molar mas</em>s = (0.1083 mol)(231.735 g/mol) = <em>25.11 g.</em>

7 0
3 years ago
What is avogadros number
Ad libitum [116K]
6.022*10^23 is the number
5 0
3 years ago
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