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Cerrena [4.2K]
3 years ago
5

Is ketchup a heterogeneous or homogeneous mixture? Explain your reasoning.

Chemistry
2 answers:
Norma-Jean [14]3 years ago
5 0
Homogeneous because everything is mixed together evenly.
Natali5045456 [20]3 years ago
4 0
Homogeneous because the mixture is mixed well and you cant see the ingredients. 
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Does water roll or slide in wax paper?
ruslelena [56]
Water rolls on the paper, due to different polarity 
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3 years ago
What piece of kitchen equipment operates between 1 -4 degrees celsius
Nikitich [7]
Thermal emersion circulators is what it is called
7 0
3 years ago
Rank the following solutions from least polar to most polar. Rank on a scale of 1-4: 1 being the least polar and 4 being the mos
Vlada [557]

Answer:

The answer is given below

Explanation:

When electronegativity difference arises between the bonded atoms, then a molecule is polar.

When electros are shared equally between the bonded atoms or when the polar bonds in a bigger molecule cancels out each other, then a a molucule is non polar.

(a) 50% isopropanol/H2O,--- 2 (second least polar)

(b) 25% isopropanol/H2O,----- 3 (third least polar)

(c) pure water----- is 4 (most polar)

(d) 70% isopropanol/H2O. 1 (least polar)

3 0
4 years ago
What is the pH of a 1.9 M solution of HClO4?
Sliva [168]
The compound HClO4, when placed in water, will dissociate into the ions, H+ and ClO4-. Therefore, the 2.0 M solution will also form 2.0 M H+. The pH is calculated through the equation,
pH = -log[H+]
Substituting,
pH = -log[2] = -0.3
Thus, the pH of the solution is -0.3.
5 0
3 years ago
3. What is the energy of a photon whose frequency is 5.2 x 1015 Hz? Use the equation: E = hxv
anzhelika [568]

Answer:

3. 3.45×10¯¹⁸ J.

4. 1.25×10¹⁵ Hz.

Explanation:

3. Determination of the energy of the photon.

Frequency (v) = 5.2×10¹⁵ Hz

Planck's constant (h) = 6.626×10¯³⁴ Js

Energy (E) =?

The energy of the photon can be obtained by using the following formula:

E = hv

E = 6.626×10¯³⁴ × 5.2×10¹⁵

E = 3.45×10¯¹⁸ J

Thus, the energy of the photon is 3.45×10¯¹⁸ J

4. Determination of the frequency of the radiation.

Wavelength (λ) = 2.4×10¯⁵ cm

Velocity (c) = 3×10⁸ m/s

Frequency (v) =?

Next, we shall convert 2.4×10¯⁵ cm to metre (m). This can be obtained as follow:

100 cm = 1 m

Therefore,

2.4×10¯⁵ cm = 2.4×10¯⁵ cm × 1 m /100 cm

2.4×10¯⁵ cm = 2.4×10¯⁷ m

Thus, 2.4×10¯⁵ cm is equivalent to 2.4×10¯⁷ m

Finally, we shall determine the frequency of the radiation by using the following formula as illustrated below:

Wavelength (λ) = 2.4×10¯⁷ m

Velocity (c) = 3×10⁸ m/s

Frequency (v) =?

v = c / λ

v = 3×10⁸ / 2.4×10¯⁷

v = 1.25×10¹⁵ Hz

Thus, the frequency of the radiation is 1.25×10¹⁵ Hz.

8 0
2 years ago
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