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2 years ago

The flamability (burns) is a physical change ?

Chemistry

2 answers:

kaheart [24]2 years ago

7 0

Nah not much of a physical change

NikAS [45]2 years ago

5 0

Flammability is a chemical change because when you burn something, it no longer has the same properties.

You might be interested in

How many chloride ions are in 2.6 moles of CaCl2?

Rama09 [41]

Answer:

31.31× 10²³ number of Cl⁻ are present in 2.6 moles of CaCl₂ .

Explanation:

Given data:

Number of moles of CaCl₂ = 2.6 mol

Number of Cl₂ ions = ?

Solution:

CaCl₂ → Ca²⁺ + 2Cl⁻

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

In one mole of CaCl₂ there are two moles of chloride ions present.

In 2.6 mol:

2.6×2 = 5.2 moles

1 mole Cl⁻ = 6.022 × 10²³ number of Cl⁻ ions

5.2 mol × 6.022 × 10²³ number of Cl⁻ / 1mol

31.31× 10²³ number of Cl⁻

8 0

2 years ago

What determines the strength of a solute as an electrolyte?

timama [110]

Solutes become electrolytes by ionizing. Ionic compounds therefore make good electrolytes; covalent compounds don't.

8 0

3 years ago

Write this number using scientific notation: 0.000735

bixtya [17]

0.000735 in scientific notation is 7.35 x 10^-4

5 0

2 years ago

John recently purchased a High Definition plasma television and needed to have it installed. The installers told John that for t

ioda

Ductility - a materials ability to stretch, ie if you pull it apart does it stretch to a wire.

density - ratio of volume to mass

conductivity - materials ability to conduct a current.

hopefully with these definitions you can figure out the answer.

8 0

3 years ago

Read 2 more answers

An analytical chemist weighs out 0.188 g of an unknown triprotic acid into a 250 mL volumetric flask and dilutes to the mark wit

Anon25 [30]

Answer: The molar mass of unknown triprotic acid is 97.66 g/mol

Explanation:

To calculate the molarity of acid, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of triprotic acid

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is NaOH.

We are given:

$n_1=3\\M_1=?M\\V_1=250mL\\n_2=1\\M_2=0.0600M\\V_2=95.9mL$

Putting values in above equation, we get:

$3\times M_1\times 250=1\times 0.0600\times 95.9\\\\M_1=0.0077M$

To calculate the molecular mass of solute, we use the equation used to calculate the molarity of solution:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$

We are given:

Molarity of solution = 0.0077 M

Given mass of triprotic acid = 0.188 g

Volume of solution = 250 mL

Putting values in above equation, we get:

$0.0077M=\frac{0.188\times 1000}{\text{Molar mass of triprotic acid}\times 250}\\\\\text{Molar mass of triprotic acid}=97.66g/mol$

Hence, the molar mass of unknown triprotic acid is 97.66 g/mol

7 0

2 years ago