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AveGali [126]
3 years ago
11

In which phase(s) of matter are the atoms closely packed but still able to slide past each other? gas liquid

Chemistry
2 answers:
Gnesinka [82]3 years ago
6 0

the answer is liquid

lapo4ka [179]3 years ago
4 0
The answer would be liquid.
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PLEASE ANSWER I HAVE 15 MINS. Which best compares the gravitational force and the strong force?
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Which structure vibrates the hammer? <br><br> stirrup<br> ear canal<br> eardrum<br> anvil
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ANSWER: Eardrum

EXPLANATION:

The vibrations from the eardrum set the ossicles into motion. The ossicles are actually tiny bones — the smallest in the human body. The three bones are named after their shapes: the malleus (hammer), incus (anvil) and stapes (stirrup). The ossicles further amplify the sound.
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3 years ago
If a compound has a molar mass of 180 g/mol and its empirical formula is CH2O, what is its molecular formula? CH2O C2H4O2 C6H12O
irinina [24]

Its molecular formula : C₆H₁₂O₆

<h3>Further explanation  </h3>

The empirical formula(EF) is the smallest comparison of atoms of compound forming elements.  

A molecular formula(MF) is a formula that shows the number of atomic elements that make up a compound.  

(EF) n = MF

its empirical formula is CH₂O

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\tt [30]n=180\rightarrow n=6\\\\(CH_2O]_6=C_6H_{12}O_6

3 0
2 years ago
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How many electrons does Cll have?<br>​
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26 grams of 2,2 dimethyl hexane( C8H16) under goes combustion. How
sattari [20]

Answer: The CO_{2} gas occupies a space of 5.57 L at 26 Celsius and 101.75 kPa.

Explanation:

Given: Mass = 26 g

Pressure = 101.75 kPa

Convert kPa into atm as follows.

1 kPa = 0.00986923 atm\\101.75 kPa = 101.75 kPa \times \frac{0.00986923 atm}{1 kPa}\\= 1 atm

Temperature = 26^{o}C = (26 + 273) K = 299 K

Now, moles of a substance is defined as mass of substance divided by its molar mass.

As molar mass of 2,2 dimethyl hexane is 114.23 g/mol. So, its number of moles are calculated as follows.

No. of moles = \frac{mass}{molar mass}\\= \frac{26}{114.23 g/mol}\\= 0.227 mol

Formula used to calculate the volume is as follows.

PV = nRT

where,

P = pressure

V = volume

n = no. of moles

R = gas constant = 0.0821 L atm/mol K

T = temperature

Substitute the values into above formula as follows.

PV = nRT\\1 atm \times V = 0.227 mol \times 0.0821 L atm/mol K \times 299 K\\V = 5.57 L

Thus, we can conclude that the CO_{2} gas occupies a space of 5.57 L at 26 Celsius and 101.75 kPa.

3 0
2 years ago
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