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Alexandra [31]
3 years ago
12

Find the selling price of a $270 bicycle with a 24% markup.

Mathematics
2 answers:
lisov135 [29]3 years ago
6 0
1 percent of $270 is 2.70 (you just move the decimal point). then multiply your 1 percent by 24 and you have the answer. I get $64.80, doing it on paper.
Add the 24 percent to the original price and you have your retail price: $334.80.  If you have a calculator, check my maths.
lord [1]3 years ago
5 0
1) Make 24% as a decimal, which is 0.24. 
<span>2) Add 1.0 to 0.24 because it's a mark </span>up<span> to make it </span>1.24<span>. </span>
<span>3) Multiply 1.24 with $270 = $334.80.

</span><span>answer:$334.80</span>
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What is w=138.24/9.6×3.2
RSB [31]
4.5 is the answer.
First you multiply 9.6x3.2 which gives us 30.72 
Then you divide 138.24 by 30.72 which equals 4.5
Hope this helps
5 0
3 years ago
Read 2 more answers
Can you answer this question please?
Alika [10]

answer is 8n^1/3

 see attached picture:

5 0
3 years ago
Can someone help me for this question please? I just keep getting wrong answer! Pls someone explain to me step by step! ASAP!!!
Kobotan [32]

Answer:

  84 feet

Step-by-step explanation:

This problem involves several steps. The first step is to realize that the given figure does not show the required number of vertical stringers. It shows 5, but there will be 7 of them. The given diagram is helpful in that it shows a vertical stringer on the centerline of the arches.

The second step is to write a function that will tell you how long the stringer will be. I find it convenient to write the equation for an arch shape such as this using the parent function h(x) = 1-x^2. This parent function gives an arch of height 1 and width 1 from center (a total width of 2). You want an arch that is 16 ft high and 40 ft wide (one side from center), so you must scale this parent function both horizontally (by 40) and vertically (by 16). It becomes ...

  H(x) = 16(1 -(x/40)^2)

The taller arch is twice this height, so the length of a vertical stringer at position x is

  vertical length = 2H(x) -H(x) = H(x)

That is, the function H(x) we defined can be used to find the length of the stringers.

The third step is to find the stringer lengths. It can save some energy if you realize that the problem is symmetrical, so that the stringer at x=-30 is the same length as the one at x=30. We need to find stringer lengths every 10 feet from -40 feet to +40 feet. Of course, the ones at ±40 feet are zero length, because that is where the two arches meet.

  H(-30) = 16(1 -(3/4)^2) = 7

  H(-20) = 16(1 -(1/2)^2) = 12

  H(-10) = 16(1 -(1/4)^2) = 15

  H(0) = 16

Then the fourth step is to add up the stringer lengths, rounding the result as required.

  7 +12 +15 +16 +15 +12 +7 = 16 + 2(34) = 84 . . . . feet (no rounding needed)

Finally, you need to answer the question asked:

  The sum of vertical stringer lengths is 84 feet.

5 0
3 years ago
Please help asap!! Due today!
Gwar [14]

Answer:

No for the first

Step-by-step explanation:

Sorry i do not know the second one bt the first one is No it is not a right angle

5 0
2 years ago
PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!
Lunna [17]

−5 < a − 4 < 2

+4 +4

-1 < a < 6

Answer is B. The second one


7 0
3 years ago
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