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vekshin1
2 years ago
10

15 more than the quotient of 24 and a number x

Mathematics
1 answer:
iris [78.8K]2 years ago
4 0

Answer:

24x + 15

Step-by-step explanation:

You multiply 24 and x together, then add 15 to the sum.

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The table shows the cost of renting ski equipment at a ski lodge. Write a linear function f for the sequence. Then graph the fun
Bingel [31]

Answer:

<u>y=5x+7</u>

<u>or</u>

<u>f(x)=5x+7</u>

Step-by-step explanation:

Slope (m) = 5

Y-intercept (b) = 7

Using the equation y=mx+b, you can find m and b to make y=5x+7.

Steps:

(1, 12) (2, 17)                          formula: y2-y1 / x2-x1 = m

17-12= 5

 2-1 = 1

5/1=5

m=5

12=5(1)+b

12=5+b

7=b

17=5(2)+b

17=10+b

7=b

<u>Answer: y=5x+7</u>

<u>or</u>

<u>f(x)=5x+7</u>

6 0
2 years ago
The blue segment below is a diameter of 0. What is the length of the radius of the circle
Norma-Jean [14]

Answer:

Option (B) 5.1 units

Step-by-step explanation:

Since the radius of the circle is half of its diameter and given the diameter of the circle is 10.2 units then the radius would be $ \frac{10.2}{2} = 5.1 units $

Thus the answer.

3 0
3 years ago
Read 2 more answers
Cone A has a radius of 2 inches and a height of 3 inches. In cone B, the height is the same, but the radius is doubled. Calculat
wlad13 [49]

Answer: Option C.

Step-by-step explanation:

Use the formula for calculate the volume of a cone:

V=\frac{1}{3}\pi r^2h

Where r is the radius and h is the height.

Volume of the cone A:

V_A=\frac{1}{3}\pi (2in)^2(3in)=12.56in^3

Volume of the cone B:

If the height of the cone B and the height of the cone A are the same , but the radius of the cone B is doubled, then its radius is:

r_B=2r_A\\r_B=2*2in\\r_B=4in

Then:

V_B=\frac{1}{3}\pi (4in)^2(3in)=50.26in^3

Divide V_B by V_A:

\frac{V_B}{V_A}=\frac{50.26in^3}{12.56in^3}=4

Therefore: When the radius is doubled, the resulting volume is 4 times that of the original cone.

5 0
3 years ago
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Help me asap please
iren [92.7K]

A(-3, -1); B(2, -1), C(2, 3)

You can read the length of AB and BC.

|AB| = 5

|BC| = 4

Use the Pythagorean theorem:

|AC|^2=5^2+4^2\\\\|AC|^2=25+16\\\\|AC|^2=41\to|AC|=\sqrt{41}\\\\|AC|\approx6.4

The perimeter:

P=|AB|+|BC|+|AC|\\\\P=5+4+6.4=15.4

7 0
3 years ago
For the rhombus below, find the measure of angles 1,2,3 and 4.
Alexus [3.1K]

Answer:

∠1 is 33°

∠2 is 57°

∠3 is 57°

∠4 is 33°

Step-by-step explanation:

First off, we already know that ∠2 is 57° because of alternate interior angles.

Second, it's important to know that rhombus' diagonals bisect each other; meaning they form 90° angles in the intersection. Another cool thing is that the diagonals bisect the existing angles in the rhombus. Therefore, 57° is just half of something.

Then, you basically just do some other pain-in-the-butt things after.

Since that ∠2 is just the bisected half from one existing angle, that means that ∠3 is just the other half; meaning that ∠3 is 57°, as well.

Next is to just find the missing angle ∠1. Since we already know ∠3 is 57°, we can just add that to the 90° that the diagonals formed at the intersection.

57° + 90° = 147°

180° - 147° = 33°

∠1 is 33°

Finally, since that ∠4 is just an alternate interior angle of ∠1, ∠4 is 33°, too.

5 0
3 years ago
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