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Llana [10]
3 years ago
9

The graph of f ′ (x), the derivative of f of x, is continuous for all x and consists of five line segments as shown below. Given

f (0) = 7, find the absolute minimum value of f (x) over the interval [–3, 0].
A. 0
B. 2.5
C. 4.5
D. 11.5

Mathematics
1 answer:
ivolga24 [154]3 years ago
4 0

Answer:

B

Step-by-step explanation:

f(0) - f(-3) = area under f'(x) from x=0 to x=3.

We can find the area under f'(x) in this interval by finding the area of the triangle formed by the line.

A = 1/2 b h

A = 1/2 (3) (3)

A = 4.5

f(0) - f(-3) = 4.5

Since f(0) = 7:

7 - f(-3) = 4.5

f(-3) = 7 - 4.5

f(-3) = 2.5

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Vlad1618 [11]

Given:

The graph of linear function.

To find:

The slope intercept form of the linear equation from the given graph.

Solution:

The slope intercept form of a linear function is:

y=mx+b

From the given graph it is clear that the graph passes through the points (1,300) and (4,800).

The equation of line is

y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)

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y-300=\dfrac{500}{3}(x-1)

y-300=\dfrac{500}{3}x-\dfrac{500}{3}

Adding 300 on both sides, we get

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y=\dfrac{500}{3}x+\dfrac{900-500}{3}

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Therefore, the required equation is y=\dfrac{500}{3}x+\dfrac{400}{3}.

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Answer: Yes it is

Step-by-step explanation:

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