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Llana [10]
3 years ago
9

The graph of f ′ (x), the derivative of f of x, is continuous for all x and consists of five line segments as shown below. Given

f (0) = 7, find the absolute minimum value of f (x) over the interval [–3, 0].
A. 0
B. 2.5
C. 4.5
D. 11.5

Mathematics
1 answer:
ivolga24 [154]3 years ago
4 0

Answer:

B

Step-by-step explanation:

f(0) - f(-3) = area under f'(x) from x=0 to x=3.

We can find the area under f'(x) in this interval by finding the area of the triangle formed by the line.

A = 1/2 b h

A = 1/2 (3) (3)

A = 4.5

f(0) - f(-3) = 4.5

Since f(0) = 7:

7 - f(-3) = 4.5

f(-3) = 7 - 4.5

f(-3) = 2.5

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RideAnS [48]

Answer: HI ^_^

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Step-by-step explanation:

hope it helps

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3 0
3 years ago
Read 2 more answers
Write an equation for the nth term of the arithmetic sequence.<br> 17, 12, 7, 2, ...<br> an=
Lorico [155]

Answer:

An equation for the nth term of the arithmetic sequence 17, 12, 7, 2 is 17-5n.

Step-by-step explanation:

Given,

first term(a)=17

common difference (d)=t2-t1

=12-17

=-5

nth term of the arithmetic sequence = a+n×d

=17+n×-5

=17-5n

5 0
3 years ago
Here are summary statistics for randomly selected weights of newborn​ girls: nequals=174174​, x overbarxequals=30.930.9 ​hg, seq
MaRussiya [10]

Answer:

The 95% confidence interval would be given by (29.780;32.020)  

Step-by-step explanation:

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=30.9 represent the sample mean for the sample  

\mu population mean (variable of interest)

s=7.5 represent the sample standard deviation

n=174 represent the sample size  

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=174-1=173

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a tabel to find the critical value. The excel command would be: "=-T.INV(0.025,173)".And we see that t_{\alpha/2}=1.97, this value is similar to the obtained with the normal standard distribution since the sample size is large to approximate the t distribution with the normal distribution.  

Now we have everything in order to replace into formula (1):

30.9-1.97\frac{7.5}{\sqrt{174}}=29.780    

30.9+1.97\frac{7.5}{\sqrt{174}}=32.020

So on this case the 95% confidence interval would be given by (29.780;32.020)    

The value 29.6 is not contained on the interval calculated.

5 0
3 years ago
What is the place if 6 in 34.76
Paladinen [302]
The answer is Hundredths place
8 0
3 years ago
Read 2 more answers
Refer to the various selling prices of various homes in a community that follow the normal distribution with mu (population mean
blsea [12.9K]

Answer:

0.43715

Step-by-step explanation:

We solve using z score calculator

z = (x-μ)/σ, where

x is the raw score

μ is the population mean = $276,000

σ is the population standard deviation = 32,000

For x = $276,000

z = 276,000 - 276,000/32000

z = 0

Probability value from Z-Table:

P(x = 276000) = 0.5

For x = $325,000

z = 325,000 - 276,000/32000

z = 1.53125

Probability value from Z-Table:

P(x = 325000) = 0.93715

The probability that the next house in the community will sell for between $276,000 and $325,000 is

P(x = 325000) - P(x = 276000)

= 0.93715 - 0.5

= 0.43715

8 0
3 years ago
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