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kari74 [83]
3 years ago
15

HELP PLEase!!! Which option is an outcome of a project stated in quantifiable terms?

Computers and Technology
1 answer:
dimulka [17.4K]3 years ago
4 0

Answer: C) a 10 percent increase in efficiency of sales of a particular product line over one year

The term "quantifiable" means that we can attach a number to it. Specifically, a number in which we can do math operations upon it. Something like telephone numbers or serial numbers don't really count as quantifiable entities. They are qualitative variables instead. So you have to be careful what numbers you run into. In this case, "10 percent increase in efficiency" is quantitative and fits what we're after.

A 10% increase corresponds to the multiplier 1.10; for instance, if you had sales of 40 million dollars one year, then a 10% increase is 1.10*40 = 44 million in sales. This is one example where we apply a math operation (specifically multiplication) on the value in question.

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You are tasked with implementing a recursive function void distanceFrom(int key) on the IntList class (provided). The function w
sashaice [31]

Answer:

\*IntList.h*\

#ifndef __INTLIST_H__

#define __INTLIST_H__

#include <ostream>

using namespace std;

struct IntNode {

int data;

IntNode *next;

IntNode(int data) : data(data), next(nullptr) {}

};

class IntList {

private:

IntNode *head;

public:

/* Initializes an empty list.

*/

IntList() : head(nullptr) {

}

/* Inserts a data value to the front of the list.

*/

void push_front(int val) {

if (!head) {

head = new IntNode(val);

} else {

IntNode *temp = new IntNode(val);

temp->next = head;

head = temp;

}

}

/* Outputs to a single line all of the int values stored in the list, each separated by a space.

This function does NOT output a newline or space at the end.

*/

friend ostream & operator<<(ostream &out, const IntList &rhs) {

if (rhs.head) {

IntNode *curr = rhs.head;

out << curr->data;

for (curr = curr->next ; curr ; curr = curr->next) {

out << ' ' << curr->data;

}

}

return out;

}

/* Update all nodes previous to the node containing the passed in integer to be the distance from that node

(1 for the node directly preceding it)

No return value. Works by calling a recursive function (defined below).

*/

void distanceFrom(int);

private:

/* Recursive helper functions that will (1) find the key passed in and then

(2) recursively update the nodes preceding it to contain their distance from the node containing the key.

If the key is not found, update with the distance from the end, with the last node having the value of 1.

*/

int searchAndModify(IntNode *, int);

};

#endif

\*IntList.cpp*\

#include "IntList.h"

void distanceFrom(int key) {

head->data = searchAndModify(head, key);

}

int searchAndModify(IntNode *curr, int key) {

if (key == head->data) {

return(curr->data);

}

/* if key found or last node found , then return 0 */

if (curr==nullptr || key==curr->data) {

return 0;

}

if(curr != nullptr && key != curr->data) {

curr->data = 1 + searchAndModify(curr->next, key);

return(curr->data);

}

}

/* main.cpp */

#include <iostream>

using namespace std;

#include "IntList.h"

int main() {

int testNum;

cout << "Enter test number: ";

cin >> testNum;

cout << endl;

if (testNum == 1) {

IntList test1;

test1.push_front(-3);

test1.push_front(1);

test1.push_front(5);

test1.push_front(8);

test1.push_front(2);

test1.push_front(4);

test1.push_front(0);

test1.push_front(9);

cout << "Key is 8" << endl;

cout << "Before: " << test1 << endl;

test1.distanceFrom(8);

cout << "After : " << test1 << endl;

}

// Test exists function

if (testNum == 2) {

IntList test2;

test2.push_front(-3);

test2.push_front(8);

test2.push_front(10);

test2.push_front(-42);

test2.push_front(3);

test2.push_front(58);

cout << "Key is -3" << endl;

cout << "Before: " << test2 << endl;

test2.distanceFrom(-3);

cout << "After : " << test2 << endl;

}

system("pause");

return 0}

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