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kari74 [83]
3 years ago
15

HELP PLEase!!! Which option is an outcome of a project stated in quantifiable terms?

Computers and Technology
1 answer:
dimulka [17.4K]3 years ago
4 0

Answer: C) a 10 percent increase in efficiency of sales of a particular product line over one year

The term "quantifiable" means that we can attach a number to it. Specifically, a number in which we can do math operations upon it. Something like telephone numbers or serial numbers don't really count as quantifiable entities. They are qualitative variables instead. So you have to be careful what numbers you run into. In this case, "10 percent increase in efficiency" is quantitative and fits what we're after.

A 10% increase corresponds to the multiplier 1.10; for instance, if you had sales of 40 million dollars one year, then a 10% increase is 1.10*40 = 44 million in sales. This is one example where we apply a math operation (specifically multiplication) on the value in question.

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<h3>What is Location?</h3>

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The most popular input device of a computer is a(n) ____.
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A keyboard and a mouse

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As a member of the accounting group,
Anastasy [175]

Answer:

rtg

Explanation:

rth

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Question is attached as image, please help :&gt;
harkovskaia [24]

Answer:

Proved

Explanation:

Given

X = (a.\bar b)+(\bar a.b)

(a + b)\ .  \frac{}{a.b}

Required

Find out why they represent the same

To do this, we simplify either (a + b)\ .  \frac{}{a.b} or X = (a.\bar b)+(\bar a.b)

In this question, I will simplify (a + b)\ .  \frac{}{a.b}

Apply de morgan's law

(a + b)\ .  \frac{}{a.b} = (a + b) . (\bar a + \bar b)

Apply distribution property

(a + b)\ .  \frac{}{a.b} = a.\bar a + a.\bar b + \bar a . b + b . \bar b

To simplify, we apply the following rules:

a.\bar a = 0 --- Inverse law

b.\bar b = 0 --- Inverse law

So, the expression becomes

(a + b)\ .  \frac{}{a.b} = 0 + a.\bar b + \bar a.b + 0

(a + b)\ .  \frac{}{a.b}  = a.\bar b + \bar a.b

Rewrite as:

(a + b)\ .  \frac{}{a.b}  = (a.\bar b)+(\bar a.b)

From the given parameters:

X = (a.\bar b)+(\bar a.b)

This implies that:

(a + b)\ .  \frac{}{a.b} when simplified is X or (a.\bar b)+(\bar a.b)

3 0
3 years ago
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