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2 years ago

Please help Find P2 if possible.

Mathematics

1 answer:

stich3 [128]2 years ago

7 0

Answer:

It's Impossible.

Matrix can only be raised to a power if it has same number of rows and columns

Step-by-step explanation:

$P= \begin{pmatrix}1&3&2\\ 3&2&1\end{pmatrix}\\\\P^2 = \begin{pmatrix}1&3&2\\ 3&2&1\end{pmatrix}^2\\\\\mathrm{Dimensions\:of\:matrix}\:\\\begin{pmatrix}1&3&2\\ 3&2&1\end{pmatrix}:\:2x3\\\mathrm{Matrix\:can\:only\:be\:raised\:to\:a\:power,\\\:if\:it\:has\:same\:number\:of\:rows\:and\:columns}$

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Fittoniya [83]

Answer:

Step-by-step explanation

5 0

3 years ago

Read 2 more answers

2. Write a function that models the relationships among x, y, and r. (Hint: Use the Pythagorean theorem.) Then solve the equatio

In-s [12.5K]

Answer:

$r^{2} = \sqrt{y^{2} + x^{2} }$

Then just plug in the values depending on the bridge you chose I'm pretty sure

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3 years ago

The ticket sales for Fist Bump are as follows:

Fed [463]

Notice that the denominators are 3 and 7, which are factors of 21.

So express all the fractions with denominator 21:

On Monday $\frac{1}{7} = \frac{1}{7} * \frac{3}{3} = \frac{3}{21}$ are sold
On Tuesday $\frac{1}{3} = \frac{1}{3} * \frac{7}{7} = \frac{7}{21}$ are sold
On Wednesday $\frac{2}{7} = \frac{2}{7} * \frac{3}{3} = \frac{6}{21}$ are sold

by Thursday $\frac{3}{21}+\frac{7}{21}+\frac{6}{21} = \frac{3+7+6}{21}= \frac{16}{21}$ of the tickets was sold.

Answer: $\frac{16}{21}$

8 0

3 years ago

Please answer -24x + 16y

Alex787 [66]

Answer:

-8(3x-2y)

Step-by-step explanation:

Factor out each number because 8 times 3 equals 24

And -2 times -8 is 16

3 0

3 years ago

Celia sells calendars for fundraiser. Each calendar cost $9. She sells 16 calendars to her family members and 14 calendars to th

Sunny_sXe [5.5K]

Answer:

Since Her goal is to earn $ 300 , but now she is earning only $270 ,Hence Celia will not achieve her goal .

Step-by-step explanation:

Given as :

The cost of each calendar = $ 9

The number of calendar sold to the family = 16

The number of calendar sold to the neighborhood = 14

So, Total number of calendar sold by Celia = The number of calendar sold to the family + The number of calendar sold to the neighborhood

i.e Total number of calendar sold by Celia = 16 + 14 = 30

∵ The cost of each calendar = $ 9

∴ The cost of 30 calendar = $ 9 × 30 = $ 270

Since Her goal is to earn $ 300 , but now she is earning only $270 ,Hence Celia will not achieve her goal . Answer

5 0

3 years ago