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sleet_krkn [62]
2 years ago
15

The question is in the photo above plz answer

Mathematics
1 answer:
frutty [35]2 years ago
5 0

Answer:

surface area of cuboid=2(lb+bh+hl)

surface area of cuboid=2(12×5+5×2+2×12 )

surface area of cuboid=188in²

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Find zeros and y intercept of each function algebraically f(x)=x^3-10x^2+24x
monitta

Answer:

The zeros are 0, 4, 6.

The y-intercept is 0.

Step-by-step explanation:

f(x) = x^3 - 10x^2 + 24x

x^3 - 10x^2 + 24x = 0

x(x^2 - 10x + 24) = 0

x(x - 4)(x - 6) = 0

x = 0 or x - 4 = 0 or x - 6 = 0

x = 0 or x = 4 or x = 6

y-intercept:

Since x = 0 is a root, that means that the point (0, 0) is part of the function. That makes the y-intercept 0.

You can also solve for the y-intercept by letting x = 0 in the function and solving for f(0).

Let x = 0.

f(0) = 0^3 - 10(0^2) + 24(0)

f(0) = 0

y-intercept: 0

5 0
3 years ago
If f(x) = -(-2x - 5), what is f(-5)?
sammy [17]

Answer:

f(-5)=-5

Step-by-step explanation:

f(-5)= -((-2)(-5)-5)

     = -(10-5)

     = -(5)

     = -5

4 0
3 years ago
Read 2 more answers
Fred buys a video game disk for 4$. there was a discount of 20%. what is the sales price?
enyata [817]
The answer is this: $3.60

4 x 10 = 40 - 0.4 = 3.6 



4 0
3 years ago
Read 2 more answers
Which explains how to find the quotient of the division below? Negative 3 and one-third divided by StartFraction 4 over 9 EndFra
Ulleksa [173]

Answer:

(B) Write Negative 3 and one-third as Negative StartFraction 10 over 3 EndFraction, and find the reciprocal of StartFraction 4 over 9 EndFraction as StartFraction 9 over 4 EndFraction. Then, rewrite Negative 3 and one-third divided by StartFraction 4 over 9 EndFraction as Negative StartFraction 10 over 3 EndFraction times StartFraction 9 over 4 EndFraction. The quotient is Negative 7 and StartFraction 6 over 12 EndFraction = Negative 7 and one-half.

Step-by-step explanation:

To find the quotient of the division:

-3\dfrac13 \div \dfrac49

Step 1: \text{Write}$ $ -3\dfrac13$ as $ -\dfrac{10}{3}

-3\dfrac13 \div \dfrac49 =  -\dfrac{10}{3} \div \dfrac49

Step 2: Find the reciprocal of  \dfrac94

-\dfrac{10}{3} \times \dfrac94\\=-7\dfrac12

4 0
3 years ago
Read 3 more answers
The Ohio Department of Agriculture tested 203 fuel samples across the state in 1999 for accuracy of the reported octane level. F
OlgaM077 [116]

Answer:

The Sample size is 1918.89035

Step-by-step explanation:

Consider the provided information.

It is given that 14 out of 105 samples failed.

Therefore p = 14/105 = 0.13 3... and q=1-0.133=0.867

Samples would be needed to create a 99 percent confidence interval.

Subtract the confidence level from 1, then divide by two.

\frac{(1 -0.99)}{2}=0.005

By standard normal table z=2.5758≈2.58

Calculate the sample size as:

n=\frac{z^2pq}{e^2}

Where,  e is the margin of error,

Substitute the respective values.

n=\frac{(2.58)^2(0.133)(0.867)}{(0.02)^2}=1918.89

Hence, the Sample size is 1918.89035

4 0
3 years ago
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