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3 years ago

I put more points, sorry

Mathematics

1 answer:

Murljashka [212]3 years ago

3 0

Answer:

I dont understand. It isnt clear on what they want you to do.

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2+6y+4m-2y+8-m C-3+2x+2x+6x+4x

Alex777 [14]

Answer:

1. 2+6y+4m-2y+8-m

10+4y+3m

2. C-3+2x+2x+6x+4x

c+11

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Step-by-step explanation:

for question one-

if you combine all like terms you get a result of 10, 4y, and 3m. you create this into the proper expression and keep all the different terms separate, youre good to go !!

for question two-

once again, combine all like terms!! this is a very importiant step and as you go, you can cross off the terms you have combined. so you will get c and 11. and as i said previously, make them into a proper expression. so in result you will get c+11.

i hope i helped!! have a great day or night :)

5 0

3 years ago

(4/-5) ÷ (-3/10) A) 12/50 B) -18.6 C) 8/3 D) -12/50

gregori [183]

Answer:

2.666666667 is the answer

4 0

4 years ago

Read 2 more answers

How many band uniforms can be made with 131 3/4 yards of fabric if each uniform requires 3 7/8 yards

ElenaW [278]

The question can be read as how many $3 \frac{7}{8}$ can be made out of $131 \frac{3}{4}$

$131 \frac{3}{4}$ ÷ $3 \frac{7}{8}$ ⇒ We need to change each mixed number into an improper fraction

$131 \frac{3}{4}= \frac{[131*4]+3}{4}= \frac{527}{4}$
$3 \frac{7}{8}= \frac{[3*8]+7}{8} = \frac{31}{8}$

$\frac{527}{4}$ ÷ $\frac{31}{8}$
$\frac{527}{4}$ × $\frac{8}{31}$
$\frac{527*8}{4*31}= \frac{4216}{248} =17$

Answer: 17 uniform

7 0

3 years ago

Find an exact value.

Westkost [7]

Answer:

$\displaystyle \cos\left(-\frac{7\,\pi}{12}\right) = \frac{\sqrt{2} - \sqrt{6}}{4}$ .

Step-by-step explanation:

Convert the angle $\displaystyle \left(-\frac{7\, \pi}{12}\right)$ to degrees:

$\displaystyle \left(-\frac{7\, \pi}{12}\right) = \left(-\frac{7\, \pi}{12}\right) \times \frac{180^\circ}{\pi} = -105^\circ$ .

Note, that $\left(-105^\circ\right)$ is the sum of two common angles: $\left(-45^\circ\right)$ and $\left(-60^\circ\right)$ .

$\displaystyle \cos\left(-45^\circ\right) = \cos\left(45^\circ\right) = \frac{\sqrt{2}}{2}$ .
$\displaystyle \cos\left(-60^\circ\right) = \cos\left(60^\circ\right) = \frac{1}{2}$ .

$\displaystyle \sin\left(-45^\circ\right) = -\sin\left(45^\circ\right) = -\frac{\sqrt{2}}{2}$ .
$\displaystyle \sin\left(-60^\circ\right) = -\sin\left(60^\circ\right) = -\frac{\sqrt{3}}{2}$ .

By the sum-angle identity of cosine:

$\cos(A + B) = \cos(A)\cdot \cos(B) - \sin(A) \cdot \sin(B)$ .

Apply the sum formula for cosine to find the exact value of $\cos\left(-105^\circ \right)$ .

$\begin{aligned}\cos\left(-105^\circ \right) &= \cos\left(\left(-45^\circ\right) + \left(-60^\circ\right)\right) \\ &= \cos\left(-45^\circ\right) \cdot \cos\left(-60^\circ\right)\right) - \sin\left(-45^\circ\right) \cdot \sin\left(-60^\circ\right)\right) \\ &= \frac{\sqrt{2}}{2} \times \frac{1}{2} - \left(-\frac{\sqrt{2}}{2}\right)\times \left(-\frac{\sqrt{3}}{2}\right) = \frac{\sqrt{2} - \sqrt{6}}{4}\end{aligned}$ .

$\displaystyle \left(-\frac{7\, \pi}{12}\right) = \left(-\frac{7\, \pi}{12}\right) \times \frac{180^\circ}{\pi} = -105^\circ$ . In other words, $\displaystyle \left(-\frac{7\, \pi}{12}\right)$ and $\left(-105^\circ\right)$ correspond to the same angle. Therefore, the cosine of $\displaystyle \left(-\frac{7\, \pi}{12}\right)\!$ would be equal to the cosine of $\left(-105^\circ\right)\!$ .