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vitfil [10]
2 years ago
6

I put more points, sorry

Mathematics
1 answer:
Murljashka [212]2 years ago
3 0

Answer:

I dont understand. It isnt clear on what they want you to do.

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Round the number 234,679 to the nearest hundred thousand
alexandr1967 [171]
To round numbers to the nearest hundred thousand, make the numbers whose last five digits are 00001 through 49999 into the next lower number that ends in 00000. For example 6,424,985 rounded to the nearest hundred thousand would be 6,400,000.
8 0
3 years ago
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5/8 = ? (Please do this one:)
SpyIntel [72]

Answer:

0.625

Step-by-step explanation:

4 0
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Mark and Robyn used base- ten blocks to show that 200 is 100 times as much as 2. Whose model makes sense? Whose model is nonsens
Dima020 [189]

Answer:

Robyn model makes more sense and Marks is nonsense.

Step-by-step explanation:

In this question ,calculations not required .All we have to do is consider each model logically .

Marks

Marks model shows 20 rather than 2 which means 200 is 10 times as much as 20. It does not make any sense.

Robyn

Robyn model shows 2 which means 200 is 100 times as much as 2 and this is not only correct but also makes sense because 100 *2=200

8 0
3 years ago
Jill's mother limited her xbox 1 playing to 10 hours per week. she played on only four days, a different amount of time each day
Brrunno [24]
You have to find out how much time she played on Saturday, Wednesday, Friday, and Sunday. Let's look at the facts.
Sunday: No info is given.
Friday: She played the least of all four days
Saturday: Twice as much as Wednesday
Wednesday: No info is given.

We can write a problem and solve from this information. Let's use the variable W for Wednesday. Saturday is 2W. So whatever number Wednesday has, multiply it by 2. All of the total numbers should equal 10.

Since Friday was played the least amount, we know that every other day has to be at least 2 hours or above, so that Friday can be 1 hour. Sunday we have no info given.

This is a bit of guess and see for this problem. Let's say that Friday was 1 hour, Wednesday was 2, Sunday was 3, and Saturday was 4. Total that equals 10. Let's check to varify that these numbers are correct.

Friday was the least amount of hours of any day, which is why it is 1.
Wednesday had 2 hours, and Saturday had twice that many, which is 4.
Sunday has 3 hours.

In short, your answer would be: Friday 1 hour, Wednesday 2 hours, Sunday 3 hours, and Saturday 4 hours. I hope I explained it wel
6 0
3 years ago
2x2 – 5x + 67 = 0<br> What would be your first step in completing the square for the equation above?
7nadin3 [17]

Answer:

The first step is to divide all the terms by the coefficient of x^{2} which is 2.

The solutions to the quadratic equation 2x^2\:-\:5x\:+\:67\:=\:0 are:

x=\frac{5}{4}+i\frac{\sqrt{511}}{4},\:x=\frac{5}{4}-i\frac{\sqrt{511}}{4}

Step-by-step explanation:

Considering the equation

2x^2\:-\:5x\:+\:67\:=\:0

The first step is to divide all the terms by the coefficient of x^{2} which is 2.

so

\frac{2x^2-5x}{2}=\frac{-67}{2}

x^2-\frac{5x}{2}=-\frac{67}{2}

Lets now solve the equation by completeing the remaining steps

Write equation in the form: x^2+2ax+a^2=\left(x+a\right)^2

Solving for a,

2ax=-\frac{5}{2}x

a=-\frac{5}{4}

\mathrm{Add\:}a^2=\left(-\frac{5}{4}\right)^2\mathrm{\:to\:both\:sides}

x^2-\frac{5x}{2}+\left(-\frac{5}{4}\right)^2=-\frac{67}{2}+\left(-\frac{5}{4}\right)^2

x^2-\frac{5x}{2}+\left(-\frac{5}{4}\right)^2=-\frac{511}{16}

Completing the square

\left(x-\frac{5}{4}\right)^2=-\frac{511}{16}

Since, you had required to know the first step in completing the square for the equation above, I hope you have got the point, but let me quickly solve the remaining solution.

For f^2\left(x\right)=a the solution are f\left(x\right)=\sqrt{a},\:-\sqrt{a}

Solving

x-\frac{5}{4}=\sqrt{-\frac{511}{16}}

x-\frac{5}{4}=\sqrt{-1}\sqrt{\frac{511}{16}}

x-\frac{5}{4}=i\sqrt{\frac{511}{16}}       ∵ Applying imaginary number rule \sqrt{-1}=i

x-\frac{5}{4}=i\frac{\sqrt{511}}{\sqrt{16}}

-\frac{5}{4}=i\frac{\sqrt{511}}{4}

x=\frac{5}{4}+i\frac{\sqrt{511}}{4}

Similarly, solving

x-\frac{5}{4}=-\sqrt{-\frac{511}{16}}

x-\frac{5}{4}=-i\frac{\sqrt{511}}{4}    ∵ Applying imaginary number rule  \sqrt{-1}=i

x=\frac{5}{4}-i\frac{\sqrt{511}}{4}

Therefore, the solutions to the quadratic equation are:

x=\frac{5}{4}+i\frac{\sqrt{511}}{4},\:x=\frac{5}{4}-i\frac{\sqrt{511}}{4}

4 0
2 years ago
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