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3 years ago

3. Explain why the planets orbit the Sun and why the orbits are slower the further

Physics

1 answer:

bazaltina [42]3 years ago

5 0

Answer:

The closer a planet is to the Sun, the stronger the Sun's gravitational pull on it, and the faster the planet moves. The farther it is from the Sun, the weaker the Sun's gravitational pull, and the slower it moves in its orbit.

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Light could be thought of as a stream of tiny particles discharged by _______ objects that travel in straight paths. *

Gelneren [198K]

Answer: Light could be thought of as a stream of tiny particles discharged by luminous objects that travel in straight paths.

Explanation:

We can define "radiation" as the transmision of energy trough waves or particles.

Particularly, light is a form of electromagnetic radiation, so the "tiny particles" of light are discharged by a radiating object, particularly we can be more explicit and call it a luminous object, in this way we are being specific about the nature of the radiation of the object.

5 0

3 years ago

A right triangle with the base labeled 40 meters and the height labeled 30 meters. The hypotenuse is a dotted arrow labeled R. W

Pepsi [2]

Answer:

The magnitude of the resultant vector R is 50 meters ⇒ 2nd answer

Explanation:

The resultant vector is the vector sum of two or more vectors

If the two vectors perpendicular to each other, then the magnitude of

the resultant vector is the square root of the sum of their squares

If x and y are two vectors perpendicular to each other, then the

magnitude of its resultant vector R is:

→ $R=\sqrt{x^{2}+y^{2}}$

Lets solve the problem

A right triangle with the base labeled 40 meters and the height labeled

30 meters

The hypotenuse is a dotted arrow labeled R

→ The base and the height of the right triangle are perpendicular

→ The hypotenuse is the resultant vector of them

Assume that x represents the base of the triangle and y represents the

height of it

By using the rule above

→ x = 40 m , y = 30 m

→ $R=\sqrt{x^{2}+y^{2}}$

→ $R=\sqrt{(40)^{2}+(30)^{2}}$

→ $R=\sqrt{1600+900}$

→ $R=\sqrt{2500}=50$

The magnitude of the resultant vector R is 50 meters

7 0

3 years ago

A teacher did an experiment to show the movement of particles in solids, liquids, and gases. The experimental set-up is shown be

ELEN [110]

Answer: Option (B) is the correct answer.

Explanation:

In a solid, molecules are held together by strong intermolecular forces of attraction. As a result, they are unable to move from their initial place but they can vibrate at their mean position.

Hence, in solid substances the molecules have low kinetic energy.

Whereas in liquids, the molecules are held by less strong intermolecular forces of attraction as compared to solids. Due to which they are able to slide past each other. Hence, they have medium kinetic energy.

In gases, the molecules are held by weak Vander waal forces. Hence, they have high kinetic energy due to which they move rapidly from one place to another leading to more number of collisions.

Hence, gases are able to expand more rapidly as compared to liquids.

Thus, we can conclude that out of the given options solid = low; liquid = medium; gas = high, combination of the state of matter and the corresponding dryer speed is correct.

8 0

4 years ago

A car is being tested for safety by colliding it with a brick wall.The 1300 kg car is initially driving towards the wall at a sp

serg [7]

Answer:

44200 N

Explanation:

To calculate the average force exerted on the car, we will use the following equation

$\begin{gathered} Ft=\Delta p \\ Ft=m(v_f-v_i) \end{gathered}$

Where F is the average force, t is the time, m is the mass, vf is the final velocity and vi is the initial velocity of the car.

Replacing t = 0.5s, m = 1300 kg, vf = -2 m/s, and vi = 15 m/s and solving for F, we get

$\begin{gathered} F(0.5s)=(1300\text{ kg\rparen\lparen-2 m/s - 15 m/s\rparen} \\ F(0.5s)=(1300\text{ kg\rparen\lparen-17 m/s\rparen} \\ F(0.5s)=-22100\text{ kg m/s} \\ F=\frac{-22100\text{ kg m/s}}{0.5\text{ s}} \\ F=-44200\text{ N} \end{gathered}$

Therefore, the average force exerted on the car by the wall was 44200 N

4 0

1 year ago

A net force of 12.0 N causes an object to increase its speed from 15.0 m/s to 18.0 m/s during a 2.0 second interval. What is the

Nat2105 [25]

Answer:

Mass of object = 8kg

Explanation:

Since a= change in v/ change in t, a= (18-16)/2

= 1.5

And F=ma
Force =12
a= 1.5
m=?

You can now solve for your unknown value of mass.

8 0

3 years ago