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WITCHER [35]
2 years ago
10

A miner develops cancer of the esophagus. Ten years before, he had been exposed to radiation when he worked for a year in a mine

. He had also smoked cigarettes for a number of years, but had quit five years ago. Which statement best describes the miner’s condition? Tests can determine whether the cancer was caused by exposure at the mine or by compounds in cigarette smoke so that a treatment can be determined. Cancer caused by exposure at the mine would have appeared while he was at the mine, so smoking is the more likely cause. The cancer is likely the result of natural exposure to radiation in the environment and not related to either the mine or smoking. It is unlikely that a specific cause can be determined, but the treatment would likely be the same in either case.
Physics
2 answers:
Salsk061 [2.6K]2 years ago
7 0

Answer:

It is unlikely that a specific cause can be determined, but the treatment would likely be the same in either case.

Explanation:

It comes to a certain point when smoking that the damage is been done to the lungs and eventually the person could develop cancer of lungs, the same with the mining, the lungs eventually get damage from breathing that dense mineral air, so the cause of the cancer would be near impossible to determine, but the treatment would be the same nontheless, so the correct option would be D.

slamgirl [31]2 years ago
3 0

D.) It is unlikely that a specific cause can be determined, but the treatment would likely be the same in either case.

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You serve a tennis ball from a height of 1.80 m above the ground. The ball leaves your racket with a velocity of 18.0 m/s at an
Delicious77 [7]

Answer:

Yes, ball will clear the net

Explanation:

First we have to find the range of projectile motion.

Data given,

Ф = 7°

Initial velocity = 18 m/s

R = (V)^2.sin2Ф/g

Now by putting values

R = 7.99 m

Now for height

h = v^2.(sinФ)^2/2g

by putting values

h = 0.245 m

Since range is less than our distance (11.83 m) from net, so still it is not clear that ball will clear the net or not.

So, now from the maximum height, we have to calculate the horizontal distance of ball to net.

Now velocity in projectile motion is in two dimensions.

V(x) = 18 m/s

V(y) = 0 m/s (because at maximum height, ball will stop and then start again, so y-component of velocity will be 0 but since there will be no acceleration along x-axis, so V(x) will be 18 m/s)

Now, by formula S = V(y)t + (1/2)gt^2

we can calculate time which is required by the ball to reach net from the maximum height it has achieved.

Now, tricky part is to calculate S, because without it we can not calculate t.

So, by data given in question, we know that the ball is served at height of 1.8 m and it achieved the height of 0.245 m. But net is at height of 1.07 m.

So, the vertical distance downward, which ball will travel from maximum height to net will be

S = 1.8 + 0.245 - 1.07

S = 0.975 m

Since we know V(y) = 0 m/s

S = (1/2)gt^2

t = (2S/g)^(1/2)

t = 0.44 s

Now time for both vertical and horizontal distance are same,

So, for horizontal distance "D(x)"

D(x) = V(x) x t (Since, no acceleration along x axis, so we can use simple formula to calculate distance)

D(x) = 18 x 0.44

D(x) = 8.029 m

Now please notice that at maximum height, range was half, so at that point ball covered distance "a"

a = 3.99 m

From maximum height to net, as we calculated, ball covered

D(x) = 8.029 m

So, total distance covered by ball

a + D(x) = 3.99 + 8.029

a + D(x) = 12.024 m

which is more than your total distance from net which is 11.83 m. So, the ball will clear the net.

7 0
2 years ago
A bicyclist makes a trip that consists of three parts, each in the same direction (due north) along a straight road. During the
Advocard [28]

Answer:

a

The total distance traveled is D  = 26760 \ m

b

The average velocity is  v_{avg} =  6.8 \ m/s

Explanation:

From the question we are told that

     The time taken for first part t_1 =  22 \ minutes = 22*60 = 1320 \ s

      The speed for the first part is  v_1 =  7.2 \ m/s

        The time taken for second part is t_2 =  36 \ minutes =  2160 \ s

        The speed for the second  part is  v_2 =  5.1 \ m/s

         The time taken for third  part is  t_3 =  8 \ minutes = 480 \ s  

          The speed for the third  part is  v_3 =  13 m/s

Generally

        distance(D)  =  velocity * time

Therefore the total distance traveled is  

         D  =  (v_1 * t_1) + (v_2 * t_2 ) + (v_3 * t_3)

substituting values

        D  =  (7.2 * 1320) + (5.1 * 2160) + (13 * 480)

        D  = 26760 \ m

Generally the average velocity is mathematically represented as

        v_{avg} =  \frac{D}{t_{total}}

Where t_{total} is the total time taken which is mathematically represented as

       t_{total}  =  1320 + 2160 + 480

      t_{total}  =3960\ s

The average velocity is

        v_{avg} =  \frac{26760}{3960}

        v_{avg} =  6.8 \ m/s

   

8 0
2 years ago
Earths energy sources include renewable and non renewableresources. name at least three sources of energy that could be used in
enot [183]

Electricity.

Solar Energy

Wind Energy


In a home, the best option as a source of energy is electricity. Though some choose to use solar energy to power their devices, electricity is more cost effective.

6 0
2 years ago
write down the total momentum for two marbles of mass,m, both moving at velocity, v. What is the kinetic energy of the system.
frosja888 [35]
Mv + mv = 2mv providing each momentum is in the same direction.
1/2 mv^2 + 1/2 mv^2  = mv^2
4 0
2 years ago
Read 2 more answers
At a given time of​ day, the ratio of the height of an object to the length of its shadow is the same for all objects. If a 4​-f
katrin2010 [14]

Answer:35.2 ft

Explanation:

Given

height of stick =4 ft

shadow length =2.8 ft

Angle of elevation of sun is

tan\theta =\frac{4}{2.8}

let the height of tree be h

as \thetawill remain same thus

tan\theta =\frac{h}{24.64}

\frac{4}{2.8}=\frac{h}{24.64}

h=35.2 ft

8 0
3 years ago
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