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MAXImum [283]
3 years ago
15

Two charged objects of +2Q and +1Q are placed a distance d from one another. The force between the objects in measured as 2F. If

the charge on BOTH objects id doubled, what will the force between them be?

Physics
1 answer:
Alex3 years ago
7 0
So new force will be 8times old force.

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What type of OS is very fast and small, and is often embedded, or built into the circuitry of a device?
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Real time operating system (RTOS)

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An archer shoots an arrow at a 74.0 m distant target, the bull's-eye of which is at same height as the release height of the arr
GuDViN [60]

A. The angle at which the arrow must be released to hit the bull's-eye is 20.7 °

B. The arrow will go over the branch.

<h3>A. How to determine the angle</h3>
  • Range (R) = 74 m
  • Initial velocity (u) = 33 m/s
  • Acceleration due to gravity (g) = 9.8 m/s²
  • Angle (θ) = ?

R = u²Sine(2θ) / g

74 = 33² × Sine (2θ) / 9.8

Cross multiply

74 × 9.8 = 33² × Sine (2θ)

725.2 = 1098 × Sine (2θ)

Divide both sides by 1098

Sine (2θ) = 725.2 / 1098

Sine (2θ) = 0.6605

Take the inverse of sine

2θ = Sine⁻¹ 0.6605

2θ = 41.3

Divide both sides by 2

θ = 41.3 / 2

θ = 20.7 °

<h3>B. How to determine if the arrow will go over or under the branch</h3>

To determine if the arrow will go over or under the branch situated mid way, we shall determine the maximum height attained by the arrow. This can be obtained as follow:

  • Initial velocity (u) = 33 m/s
  • Acceleration due to gravity (g) = 9.8 m/s²
  • Angle (θ) = 20.7 °
  • Maximum height (H) = ?

H = u²Sine²θ / 2g

H = [33² × (Sine 20.7)²] / (2 ×9.8)

H = 6.94 m

Thus, the maximum height attained by the arrow is 6.94 m which is greater than the height of the branch (i.e 3.50 m).

Therefore, we can conclude that the arrow will go over the branch

Learn more about projectile motion:

brainly.com/question/20326485

#SPJ1

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