Answer:
4N
Explanation:
Given parameters:
Weight of stone when immersed in water = 18N
Weight of water displaced = 4N
Unknown:
Weight of the stone in air = ?
Solution:
To solve this problem, we employ the Archimedes' principles.
It states that the upward buoyant force on a body is equal to the weight of the fluid displaced.
The weight of the water displaced is equal to the weight of the body.
So, the weight of the stone in air = 4N
Answer:
Assume two identical cans filled with two types of soup having same mass are rolling down on an inclined plane in same conditions. In terms of inertia different types of soup will indicate different viscosity. The higher viscosity fillings indicates more part of the soup mass is rotating together with the can’s body. This means that for the can with lower viscosity soup has a lower moment of inertia and the can with higher viscosity has higher moment of inertia while the same gravity makes them to roll.
incline angle = θ ; can's mass = m ; Radius of the can's = R , Angular acceleration for Can 1 = α1 ; Angular acceleration for Can 2 = α2
T1 = Inertia of Can with high viscosity soup
T2 = Inertia of Can with low viscosity soup
M1 rolling moment of Can 1
M2 rolling moment of Can 2
equation is given by
T1*α1 = M1 - (a)
T2*α2 = M2 - (b)
M1 = M2 = m*g*R*sin(θ). (c)
as assumed T1 > T2
from the three equation (a), (b) & (c)
the α2 > α1
Angular acceleration of Can 2 is higher than Can 1. Already stated that Can 1 has more viscous soup as compared to Can 2.
Answer:
Approximately .
Explanation:
Consider two objects of mass and . Let denote the distance between the center of mass of each object. Let denote the gravitational constant. (.)
By Newton's Law of Universal Gravitation, the size of gravitational attraction between these two objects would be:
.
In this question, and are the mass of the two planets. The distance between the two planets is (approximately the same as the distance between the center of mass of planet Earth and the center of mass of Mars.)
Apply Newton's Law of Universal Gravitation to find the size of gravitational attraction between the two planets:
.
Since , the size of gravitational attraction between the two planets would be approximately .
Answer:
Rolling = Riding a bicycle on a sidewalk
Static = Pushing a car unsuccessfully
Sliding = Pulling your computer across the bed
Fluid = Throwing a soccer ball to your friend
Answer:
11.2m³
Explanation:
Applying Archimedes principle we have it that
Weight of submarine+ weight of tank+ weight of compound air =uptrust
So
(40000+2000+37V) x9.8= (30+V) 1030 x 9.8
38910= 993V
V= 11.2m³