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Nadusha1986 [10]
3 years ago
12

Which situation best describes the act of reducing?

Physics
2 answers:
Nostrana [21]3 years ago
7 0

Answer:

paying bills online instead of sending paper through the mail

Explanation:

In today's era everyone is aware about the Climate change and wants to contribute towards environment protection. A simple technique is to follow four R's which are: Reduce, Reuse, Recycle and Refuse. The four examples given over here are examples of each R as explained below:

Reduce:  paying bills online instead of sending paper through the mail as we are reducing the paper use over here.

Reuse: donating gently used clothes and household items so that they can be reused. Using plastic bags a second time to avoid buying new ones.

Recycle & Refuse: buying products that can be recycled so they don’t end up in the trash

yawa3891 [41]3 years ago
5 0
A - i think
paying bills online?
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Help! PROJECTILE PROBLEM: A 7500-kg rocket blasts off vertically from the launch pad with a constant upward acceleration of 2.25
dsp73
Here, 

height at failure, h1 = 525 m, 
upward acceleration, a = 2.25 m/s^2, 
velocity = v m/s, 
<span>
SO, </span>
<span>
v^2 = 2*a*h = 2*2.25*525 = 2362.5 </span>
Now, acceleration, g = 9.8 m/s^2, 
<span>
SO, </span>
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heigt, h1 = v^2/2g = 2362.5 / 2*9.8 = 120.54 meters </span>
Hence, 
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a) </span>
Total height = 525+120.54 = 645.54 meters 

b) 
<span>time, for h1, t = v/g = sqrt(2362.5)/9.8 = 4.96 sec 

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3 years ago
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Calculate the force of gravity on the 0.60- kg mass if it were 1.3×107 m above Earth's surface (that is, if it were three Earth
nignag [31]
The gravitational force between two objects is given by:
F=G \frac{m_1 m_2}{r^2}
where
G is the gravitational constant
m1 and m2 are the masses of the two objects
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In this problem, the first object has a mass of m_1=0.60 kg, while the second "object" is the Earth, with mass m_2=5.97 \cdot 10^{24}kg. The distance of the object from the Earth's center is r=1.3 \cdot 10^7 m; if we substitute these numbers into the equation, we find the force of gravity exerted by the Earth on the mass of 0.60 kg:
F=G \frac{m_1m_2}{r^2}=(6.67\cdot 10^{-11}) \frac{(0.60 kg)(5.97 \cdot 10^{24} kg)}{(1.3 \cdot 10^7 m)^2}=  1.41 N
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mrs_skeptik [129]

The new gravitational attraction will be 1/4 as much

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The magnitude of the gravitational force between two objects is given by

F=G\frac{m_1 m_2}{r^2}

where

G=6.67\cdot 10^{-11} m^3 kg^{-1}s^{-2} is the gravitational constant

m1, m2 are the masses of the two objects

r is the separation between them

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