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Vladimir79 [104]
3 years ago
7

Someone pls help me with this!

Physics
1 answer:
Lina20 [59]3 years ago
5 0

Answer:

<em>F=8.87 N</em>

Explanation:

<u>Coulomb's Law </u>

The electrostatic force between two charged objects is directly proportional to the product of their charges and inversely proportional to the square of the distance between the two objects.

Written as a formula:

\displaystyle F=k\frac{q_1q_2}{d^2}

Where:

k=9\cdot 10^9\ N.m^2/c^2

q1, q2 = the objects' charge in coulomb

d= The distance between the objects  in meters

Object 1 has a charge of

q_1=-2.3\cdot 10^{-6}\ c

Object 2 has a charge of

q_2=-4.2\cdot 10^{-6}\ c

They are separated by a distance of

d = 0.099 m

Calculate the force:

\displaystyle F=9\cdot 10^9\frac{2.3\cdot 10^{-6}*4.2\cdot 10^{-6}}{0.099^2}

F=8.87 N

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An electric train operates on 800 V. What is its power consumption when the current flowing through the train's motor is 2,130 A
Musya8 [376]

Answer:

<h2>1704 kW</h2>

Explanation:

To solve for the power consumed by the trains motor we have to employ the formula for power which is

<em>Power= current * voltage</em>

Given that

voltage V= 800 V

current I= 2130 A

Substituting in the formula for power we have

Power= 2130*800=  1704000 watt

Power = 1704 kW

This is the amount of energy consumed, transferred or converted per unit of time

Hence the power consumed  by the trains motor is 1704 kW

5 0
3 years ago
Chris and Jamie are carrying Wayne on a horizontal stretcher. The uniform stretcher is 2.00 m long and weighs 100 N. Wayne weigh
BabaBlast [244]

Answer:

<h2>E. 650N</h2>

Explanation:

step one:

given

length of stretcher= 2m

weight of stretcher=100N

Wayne weighs =800N

distance of Wayne weighs from chris's end= 75cm= 0.75m

The force that Chris is exerting to support the stretcher, with Wayne on it, can be computed by taking moments of the weight of the stretcher and Wayne weighs  about Chris's end, the end result is the reaction at Chris's end

Taking moment about Chris's end

The moment of Wayne weight 75cm from Chris+ Half the weight of stretcher 1m from Chris

0.75*800+50*1=0

600+50=0

650N

6 0
3 years ago
An insulating sphere of radius 13 cm has a uniform charge density throughout its volume. 13 cm 21.6 cm 7.5 cm p If the magnitude
sdas [7]

Answer:

The value is E_1 = 49224.1 \  N/C

Explanation:

From the question we are told that

The radius is r =  13 \  cm  = 0.13 \  m

The electric field is E =   78400 \ N/C at a distance d =  7.5 \  cm  =  0.075 \  m

Generally the electric field at a distance d =  7.5 \  cm  =  0.075 \  m is mathematically represented as

E =  \frac{k *  q  * d}{r^3} Note: the reason we are using this

formula is because d < r

Here k is the coulomb constant with value k = 9*10^{9}\ kg\cdot m^3\cdot s^{-4} \cdot A^{-2}.

=> 78400=  \frac{9*10^{9} *  q  * 0.075}{0.13^3 }

Generally the electric field at a distance d =  21.6  \  cm  =  0.216 \  m is mathematically represented as

E_1 =  \frac{k *  q  }{^2} Note: the reason we are using this

formula is because d > r

Now dividing E_1\ \  by \ \ E

\frac{E_1}{78400} =  \frac{\frac{9*10^9 * q}{0.216^2} }{\frac{9*10^9 *  q *  0.075}{0.13^3} }

=> E_1 =  \frac{0.13 ^3}{ 0.075 *  0.216^2}  * 78400

=> E_1 = 49224.1 \  J

4 0
3 years ago
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