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Vladimir79 [104]
3 years ago
7

Someone pls help me with this!

Physics
1 answer:
Lina20 [59]3 years ago
5 0

Answer:

<em>F=8.87 N</em>

Explanation:

<u>Coulomb's Law </u>

The electrostatic force between two charged objects is directly proportional to the product of their charges and inversely proportional to the square of the distance between the two objects.

Written as a formula:

\displaystyle F=k\frac{q_1q_2}{d^2}

Where:

k=9\cdot 10^9\ N.m^2/c^2

q1, q2 = the objects' charge in coulomb

d= The distance between the objects  in meters

Object 1 has a charge of

q_1=-2.3\cdot 10^{-6}\ c

Object 2 has a charge of

q_2=-4.2\cdot 10^{-6}\ c

They are separated by a distance of

d = 0.099 m

Calculate the force:

\displaystyle F=9\cdot 10^9\frac{2.3\cdot 10^{-6}*4.2\cdot 10^{-6}}{0.099^2}

F=8.87 N

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The question wants me to assume that the density of my calculator
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