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Paul [167]
3 years ago
12

What is the differnce between kinetic and potential energy

Physics
2 answers:
Tems11 [23]3 years ago
5 0
I think the answer should be that, Kinetic energy is contained in a moving object, while potential energy exists in a stored form.
Zolol [24]3 years ago
5 0
Potential energy is the stored energy in an object due of its position or its configuration whereas Kinetic energy is the energy which a body possesses because of its motion.
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Which is more dense 10g of shampoo or 10kg of the same shampoo
aleksandr82 [10.1K]
Density is a property of the substance, and doesn't depend on
how much of it you have.

One drop of the shampoo and a supertanker-full of the same
shampoo have the same density.
3 0
3 years ago
The longest pipe on a certain organ is 5.34 m. (a) what is the frequency f3 (at 0.00°c) if the pipe is closed at one end?
-Dominant- [34]
For a pipe open at both ends, fund frequency (Fo) given byFo = v /2L 

v = velocity of sound = 340 m/s (at about 20ºC) 

Fo = 340/2*5.34 = 31.8 Hz 


While for the one closed at one end and open at the other end...

For a pipe open at one end, fund frequency (Fo) given byFo = v/4L 

Fo = 340/4*5.34= 15.9 Hz
7 0
3 years ago
Scientists use _____ as chemical symbols.
love history [14]
A single element on the periodic table
6 0
3 years ago
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Calculate the magnitude of the electric field at one corner of a square 1.10 m on a side if the other three corners are occupied
natka813 [3]

The direction of magnetic field is south-east and the magnitude is

23.66 × 10^{3} N/C.

Here, the magnitude of CD and BC will be cancelled, as they both are in the opposite direction and equal to each other.
the magnitude, towards the diagonal AC will result in CP, which is the direction of the electric field.


magnitude of electric field can be defined as :- The force per charge on the test charge is a straight forward way to define the size of the electric field.

To find the magnitude of the electric field use the formula

E = kq/ r^{2}

inserting the values,

E = 9. 10^{9} × 4.05 × 10^{-6} / 1.1 \sqrt{2}

E= 36.45 × 10^{3} / 1.54

E =  23.66 × 10^{3} N/C

Learn more about calculating magnitude of the electric field at one corner here:-

brainly.com/question/14922532

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3 0
1 year ago
A fish takes the bait and pulls on the line with a force of 2.3 N. The fishing reel, which rotates without friction, is a unifor
natulia [17]

Explanation:

The given data is as follows.

     Pulling force on the reel is F = T = 2.3 N

     Mass of cylinder (m) = 0.82 kg

    Radius of cylinder (r) = 0.045 m

Formula for torque pulling force on the cylinder is as follows.

           \tau = Fr

                     = I \times \alpha

Moment of inertia of the cylinder (I) is as follows.

            I = \frac{mr^{2}}{2}

  \alpha = angular acceleration of the cylinder

Hence,

                    Fr = (\frac{mr^{2}}{2}) \alpha

or,   \alpha = \frac{2F}{mr}

                   = \frac{2 \times 2.3 N}{0.82 kg \times 0.045 m}

                   = 124.66 rad/s^{2}

Amount of line pulled is h and it is in a times of 0.2 sec.

Now, linear acceleration is calculated as follows.

             a = r \alpha

                = 0.045 m \times 124.66 rad/s^{2}

                 = 5.61 m/s^{2}

Now, relation between h and acceleration as follows.

             h = v_{o}t + \frac{1}{2}at^{2}

here,   v_{o} = 0

Hence, calculate the value of h as follows.

             h = v_{o}t + \frac{1}{2}at^{2}

                = 0 + \frac{1}{2} \times 5.61 m/s^{2} \times (0.2s)^{2}

                = 0.1121 m

Thus, we can conclude that acceleration of the fishing reel is 5.61 m/s^{2} and it will pull 5.61 m/s^{2} line from the reel in 0.20 s.

7 0
3 years ago
Read 2 more answers
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