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3 years ago

Giving brainlist to whoever answers

Mathematics

1 answer:

gregori [183]3 years ago

3 0

Answer:

2/8 (could be simplified to 1/4)

Step-by-step explanation:

There are 8 total possibilities, and there are two A's

You might be interested in

What is the slope of the line below

Sphinxa [80]

6/-2 because it would have to be how tall the run is from point 0 which would be 6 and the other side is -2. Or if you need to simplify it you would get 3/-1.

6 0

3 years ago

Esther cut a square paper vertically to make two rectangle pieces. Each rectangle had a perimeter of 63 inches.

Studentka2010 [4]

Answer:

Side of the square paper = 21 inches

Step-by-step explanation:

Let the square paper is having measure of each side = a inches

Esther cut this square piece into two pieces.

Let the other side of one rectangle piece = x inches

Perimeter of this piece = 2(a + x) inches

Similarly dimensions of the other rectangular piece will be = a inches × (a - x) inches

Perimeter of this piece = 2[a + (a - x)]

Since both the rectangular pieces have the same perimeter = 63

So, 2(a + x) = 2[a + (a - x)] = 63

2(a + x) = 2(2x - x)

a + x = 2a - x

2a - a = 2x

a = 2x

x = $\frac{a}{2}$

Therefore, Perimeter = 2(a + x) = 2(a + $\frac{a}{2}$ ) = 63

$2\times \frac{3a}{2}$ = 63

3a = 63

a = 21

Therefore, measure of the sides of the square is 21 inches.

5 0

3 years ago

Determine the y-intercept of the following parabola:<br> y = (x - 3)(x + 7)

Fofino [41]

Answer:

The y intercept is -21

Step-by-step explanation:

y = (x - 3)(x + 7)

To find the y intercept, set x =0 and solve for y

y = (0-3) (x+7)

y = -3*7

y = -21

The y intercept is -21

4 0

3 years ago

Read 2 more answers

Solve the following differential equation: y" + y' = 8x^2

PtichkaEL [24]

Answer:

$y=y_p+y_h = \frac{8}{3}x^3-8x^2+16x+ C_1 + C_2e^{-x}$

Step-by-step explanation:

Let's find a particular solution. We need a function of the form $y= ax^3+bx^2+cx+d$ such that

$y'= 3ax^2+2bx+c$ and

$y''= 6ax+2b$

$y'+y''= 3ax^2+2bx+c+6ax+2b = 3ax^2+x(2b+6a)+(c+2b) = 8x^2$

then, 3a= 8, 2b+6a =0 and c+2b = 0. With the first equation we obtain

a = 8/3 and replacing in the second equation 2b+6(8/3) = 2b + 16 = 0. Then, b = -8. Finally, c = -2(-8) = 16.

So, our particular solution is $y_p= \frac{8}{3}x^3-8x^2+16x$ .

Now, let's find the solution $y_p$ of the homogeneus equation $y''+y'=0$ with the method of constants coefficients. Let $y=e^{\lambda x}$

$y'=\lambda e^{\lambda x}$

$y''=\lambda^2e^{\lambda x}$

then $\lambda e^{\lambda x}+\lambda^2 e^{\lambda x} = 0$

$e^{\lambda x}(\lambda +\lambda^2)= 0$

$(\lambda +\lambda^2)= 0$

$\lambda (1+\lambda)= 0$

$\lambda =0$ and $\lambda)= -1$ .

So, $y_h = C_1 + C_2e^{-x}$ and the solution is

$y=y_p+y_h =\frac{8}{3}x^3-8x^2+16x+ C_1 + C_2e^{-x}$ .

5 0

3 years ago

Which of the following is equivalent to 4x+5y=12?

rosijanka [135]

Answer: Slope=−

2.000

1.600

=−0.800

x−intercept=

y−intercept=

=2.40000

Step-by-step explanation:

5 0

3 years ago