The vertex of this graph is the maximum
Answer:
there is no solution
Step-by-step explanation:
Expand.
15x+35+2x=7x+10x-4515x+35+2x=7x+10x−45
2 Simplify 15x+35+2x15x+35+2x to 17x+3517x+35.
17x+35=7x+10x-4517x+35=7x+10x−45
3 Simplify 7x+10x-457x+10x−45 to 17x-4517x−45.
17x+35=17x-4517x+35=17x−45
4 Cancel 17x17x on both sides.
35=-4535=−45
5 Since 35=-4535=−45 is false, there is no solution.
No Solution
The answer is A is equal to 2
Answer: -8
Step-by-step explanation:
Answer: A. "Segment AD bisects angle CAB." is the right answer.
Step-by-step explanation:
Given : In ΔABC ,AC≅AB.
⇒∠ACB=∠CBA....(1) (∵ angles opposite to equal sides of a triangle are equal )
Now in ΔACD and ΔABD
AD=AD (common)....(2)
Here we need one more statement to prove the triangles congruent that is only statement (A) fits in it.
If AD bisects ∠CAB then ∠CAD=∠BAD..(3)
Now again Now in ΔACD and ΔABD
∠ACB=∠CBA [from (1)]
AD=AD [common]
∠CAD=∠BAD [from (3)]
So by ASA congruency criteria ΔADC≅ΔABD.
