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trapecia [35]
3 years ago
13

If sin yº = 7/q and tan yº = 7/r , what is the value of cos yº? (6 points)

Mathematics
1 answer:
olya-2409 [2.1K]3 years ago
4 0

Answer:

cos r/q is the answer,

Step-by-step explanation:

this can be seen when you elaborate sin=opposite/hypotenus and tan=opposite/adjacent by referring to the right angle triangle .

then, apply values of adjacent dan hypotenuse to cos

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A ball is thrown with an initial velocity of 70 km per second, at an angle  of 35° with the horizontal. Find the vertical and ho
oksian1 [2.3K]

Answer:

i. The horizontal component of the ball = 15.8

ii. The vertical component of the ball = 11.2

Step-by-step explanation:

A thrown ball is an example of a projectile, whose motion can be explained with respect to both horizontal and vertical components.

Horizontal component of the ball = U Cos θ

Vertical component of the ball = U Sin θ

where U is the initial velocity of the ball, and θ is the angle of projection.

Thus for the given question,

U = 70 km/hr (19.44 m/s)

θ = 35°

So that;

i. The horizontal component of the ball = 19.44 Cos 35°

                                               = 19.44 x 0.8192

                                               = 15.785

The horizontal component of the ball = 15.8.

ii. The vertical component of the ball = 19.44 Sin 35°

                                                = 19.44 x 0.5736

                                                = 11.151

The vertical component of the ball = 11.2

5 0
3 years ago
the hypotenuse of a right triangle is 15 cm and the shorter leg is 9cm find the length of the other leg
vladimir2022 [97]

Answer:


Step-by-step explanation:


3 0
3 years ago
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<span>{(1, 2), (3, 2), (5, 7)} is a function

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3 years ago
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Answer:

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Step-by-step explanation:

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a scale drawing of a building needs to be made using the scale 1 in = 190 ft. how tall will the builging in the scale drawing be
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Answer:

\boxed{\text{3 in}}

Step-by-step explanation:

1 in = 190 ft

x in = 570 ft

We can use ratio and proportion to solve this problem.

\begin{array}{cccl}\dfrac{1}{x} & = & \dfrac{190}{570} & \\\\570 & = & 190x & \text{Mutiplied by lowest common denominator (570x)}\\3 & = & x & \text{Divided each side by 3}\\\end{array}

The building will be \boxed{\textbf{3 in}} tall in the scale drawing.

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3 years ago
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