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trapecia [35]
3 years ago
13

If sin yº = 7/q and tan yº = 7/r , what is the value of cos yº? (6 points)

Mathematics
1 answer:
olya-2409 [2.1K]3 years ago
4 0

Answer:

cos r/q is the answer,

Step-by-step explanation:

this can be seen when you elaborate sin=opposite/hypotenus and tan=opposite/adjacent by referring to the right angle triangle .

then, apply values of adjacent dan hypotenuse to cos

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What is the base of a triangle with a height of 14 cm and an area of 42 square cm?
sasho [114]

Answer:

6cm

Step-by-step explanation:

area =  \frac{1}{2} \times  base \times  height \\ 42 =  \frac{1}{2}  \times b \times 14 \\ 42 =  \frac{14b}{2}  \\ 42 = 7b \\  \frac{42}{7}  =  \frac{7b}{7}  \\ base = 6cm

<em>hope</em><em> </em><em>this</em><em> </em><em>helps</em>

5 0
3 years ago
Read 2 more answers
Which is greater .513 or .5129
Vitek1552 [10]

Answer:

.513 is larger

Step-by-step explanation:

1st method is the thousandths place larger or smaller

.1 tenths

.01 hundredths

.001 thousandths

In this case the thousandths is larger for .513

2nd method

subtract the two number

.513 - .5129 = .0001

Since the number recieved is positive this means .513 is larger

7 0
2 years ago
Read 2 more answers
PLEASE HELP! 50 POINTS! IF YOURE NOT GOING TO ACTUALLY ANSWER, PLEASE DON'T SAY ANYTHING.
Fudgin [204]

Answer:

Part A:

In order to find a coterminal angle, or angles of the given angle, simply add or subtract 360 degrees of the terminal angle as many times as possible.

Part B:Simply put, coterminal angles start at 0° and end at the same place, though in different directions and multiple times around (you're probably going to want to make that sound a little more formal). Since each time around is 360°, boom

Part C: 75° is in Quadrant II, right? If I go one more time around, 75 + 360 = 435°. I can also go "backward. Starting at 0 and going clockwise, I'm going 75 fewer degrees than all the way around, so 360-75 = 285° but since I'm going "backward" 75 - 360 = -285°. One more is on you.

Step-by-step explanation:

5 0
1 year ago
Please help me with this​
Ket [755]

Answer:

its 27-78a % 367

Step-by-step explanation:

6 0
2 years ago
A random sample of 133 people was taken from a very large population. Sixty-five of the people in the sample were females.The st
rjkz [21]

Answer: 0.0433

Step-by-step explanation:

Given: Sample size : n= 133

The number of females in sample = 65

Then the proportion of females : P=\dfrac{65}{133}

The formula to calculate the standard error of the proportion is given by :-

S.E.=\sqrt{\dfrac{P(1-P)}{n}}

\Rightarrow S.E.=\sqrt{\dfrac{\dfrac{65}{133}(1-\dfrac{65}{133})}{133}}\\\\\Rightarrow\ \Rightarrow S.E.=0.0433444676341\approx0.0433

Hence, the standard error of the proportion of females is 0.0433.

6 0
3 years ago
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