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lozanna [386]
3 years ago
12

All quadratic equations written in standard form can be solved into intercept/factored form prove

Mathematics
1 answer:
BlackZzzverrR [31]3 years ago
3 0

Answer:

Refer below for detailed explanation.

Step-by-step explanation:

1. ax^2+bx+c=0.

Quadratic formula:

2. x = -b+-sqrt(b^2-4ac)/2a. .

Now two equations to find the factored form through these formulas above.

Through this identifying a,b and c.

ax^2+bx+c=0.

x^2+4x-21=0

Here a=1, b=4, and c= -21

Now applying in the quadratic formula.

x=-4+-sqrt(4^2-4(1)(-21))/2(1)

Now solve it and it becomes

x=3 or x= -7.

Another example :

x^2+3x-4=0

Here a=1, b=3 and c=-4.

X=-3+-sqrt(3^2-4(1)(-4))/2(1)

Now solve it and

x= -4 and x=1

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3 years ago
Help with 21 would be much appreciated.
umka2103 [35]

Answer:

\large\boxed{x=2\sqrt{21}\ and\ y=4\sqrt3}

Step-by-step explanation:

Look at the picture.

ΔADC and ΔCDB are similar. Therefore the sides are in proportion:

\dfrac{AD}{CD}=\dfrac{CD}{DB}

We have

AD=14-8=6\\CD=y\\DB=8

Substitute:

\dfrac{6}{y}=\dfrac{y}{8}         <em>cross multiply</em>

y^2=(6)(8)

y^2=48\to y=\sqrt{48}\\\\y=\sqrt{16\cdot3}\\\\y=\sqrt{16}\ cdot\sqrt3\\\\\boxed{y=4\sqrt3}

For x use the Pythagorean theorem:

x^2=6^2+(4\sqrt3)^2\\\\x^2=36+48\\\\x^2=84\to x=\sqrt{84}\\\\x=\sqrt{4\cdot21}\\\\x=\sqrt4\cdot\sqrt{21}\\\\\boxed{x=2\sqrt{21}}

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3 years ago
The function is f(x) is shown in this graph. Compare the slopes.
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Step-by-step explanation:

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Step-by-step explanation:

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2 years ago
The area of a rectangle is 12x^2 - 29x + 15. The width is 4x-3. What is the length of the rectangle.
allochka39001 [22]

Answer:

Step by step explanation :

Given:

it is given that in a rectangle the area is is 12x^2 -29x + 15

and the width is 4x- 3

Solution :

The rest is given in pic.

Thank u, please please mark it is Brainliest!

Hope u submit on time!

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