Answer:
65°
Step-by-step explanation:
Radii CA and CB are perpendicular to tangent lines AT and BT, so
Since angle BAT is equal to 65°, angle CAB has measure
Consider triangle ACB. This triangle is isosceles, because CA=CB as radii of the circle. Two angles adjacent to the base are congruent, thus
The sum of the measures of all interior angles in triangle is always 180°, so
Angle ACB is central angle subtended on the minor arc AB, angle APB is inscribed angle subtended on the same minor arc AB. The measure of inscribed angle is half the measure of central angle subtended on the same arc, so
Answer:
We know that the rectangular plate has measures of:
length = 7.6 ± 0.05 cm
width = 3.1 ± 0.05 cm
(the error is 0.05cm because we know that both measures are correct to one decimal place)
First, the upper bound of the length is equal to the measure of the length plus the error, this is:
L = 7.6 cm + 0.05 cm = 7.65 cm
The upper bound of the area is the area calculated when we use the upper bound of the length and the upper bound of the widht.
Remember that the area for a rectangle of length L and width W, is:
A = W*L
Then the upper bound of the area is:
A = (7.6cm + 0.05cm)*(3.1cm + 0.05cm) = 10.8 cm^2
♡ The Question ♡
-Answer --> 3/4^3
*୨୧ ┈┈┈┈┈┈┈┈┈┈┈┈ ୨୧*
♡ The Answer ♡
Fraction --> 27/64
Decimal --> 0.421875
*୨୧ ┈┈┈┈┈┈┈┈┈┈┈┈ ୨୧*
♡ The Explanation/Step-By-Step ♡
(3/4)^3
Apply Exponent Rule! --> (a/b)^c = a^c/b^c
(3/4)^3 = 3^3/4^3
3^3 = 27
= 27/4^3
4^3 = 64
= 27/64
27/64 = 0.421875
*୨୧ ┈┈┈┈┈┈┈┈┈┈┈┈ ୨୧*
♡ Tips ♡
-No tips provided!
Answer: (A) 10
<u>Step-by-step explanation:</u>
<u>Value</u> <u>Quantity</u> = <u>TOTAL Value</u>
dimes: .10 Q + 5 = .10(Q = 5)
quarters: .25 Q = .25Q
Dimes + Quarters = $4.00
.10(Q + 5) + .25Q = 4.00
.10Q + .50 + .25Q = 4.00
.50 + .35Q = 4.00
.35Q = 3.50
Q = 10
Quarters = 10
Dimes = Q + 5
= 10 + 5
= 15
<span><span> 17
</span><span>2 35
</span> 2
<span> 15
</span><span> 14
</span><span> 1
The remainder ends up to be 1. So it is 17.5. All you need to do, is to look for LCM in 35 and 2. </span></span>
