The maximum number of supply boxes she can pack in the crate is 300, if supply box is 1.5 feet tall, 1 foot wide, and 2 feet deep. The crate is 9 feet high, 10 feet wide, and 10 feet deep.
Step-by-step explanation:
The given is,
Dimensions of supply box - 1.5 feet tall, 1 foot wide, and 2 feet deep
Dimensions of crate - 9 feet high, 10 feet wide, and 10 feet deep
Step:1
Volume of supply box,
.............................(1)
Where, w - Width of box
h - Height of box
l - Length of box
From the given,
h = 1.5 feet
w = 1 foot
l = 2 feet
Equation (1) becomes,

= 3 cubic feet

Step:2
Volume of crate,
.............................(1)
Where, w - Width of box
h - Height of box
l - Length of box
From the given,
h = 9 feet
w = 10 foot
l = 10 feet
Equation (1) becomes,

= 900 cubic feet

Step:3
No. of boxes can pack in the crate,
= 
= 
= 300 supply boxes
Result:
The maximum number of supply boxes she can pack in the crate is 300, if supply box is 1.5 feet tall, 1 foot wide, and 2 feet deep. The crate is 9 feet high, 10 feet wide, and 10 feet deep.
Answer:42
Step-by-step explanation:
V= 18 + 6(4)
V= 18 + 24
V= 42
1.981: One and nine hundred eighty-one thousandths
Use your SOH CAH TOA functions to find the missing legs. Do Sin(53.1) and that is equal to opposite (PU) over hypotenuse (UG) so to solve for the PU leg just set up an equation that says sin(53.1)=PU/36 so then you can just multiply the 36 over and that gives you the leg. To find PG do adjacent over hypotenuse so Cosine, cos(53.1)=PG/36 and again just multiply over the 36 and that gives you PG