Answer:
yo i only got number 4 for you but here it goes.......: 0.70x+18y-5
Step-by-step explanation:
(0.75x - 12y) + (-5 + 6y - 0.5x)
regroup to the variables : (0.70x-0.5x) + (12y+ 6y-5)
put it together: (0.70x)+(18y-5)
you cant add unlike terms so you remove the parenthesies and your done.
Let the number of seats in section A be x, that of section B y and that of secyion C z. Then
x + y + z = 52000 . . . (1)
x = y + z . . . (2)
42x + 36y + 30z = 1960200 . . . (3)
Putting (2) into (1), gives
2x = 52000
x = 52000/2 = 26000
From (2) and (3), we have
y + z = 26000 . . . (4)
42(26000) + 36y + 30z = 1960200
36y + 30z = 1960200 - 1092000
36y + 30z = 868200 . . . (5)
(4) * 30 => 30y + 30z = 780000 . . . (6)
(5) - (6) => 6y = 88200
y = 88200/6 = 14700
From (4), z = 26000 - 14700 = 11300
Therefore, there are 26,000 seats in section A, 14,700 seats in section B and 11,300 seats in section C.
Answer:
48
Step-by-step explanation:
((8+16)÷2)×4=48
so the area would be 48
1. Her guess should be higher
2. S=6
3. 4
Answer:1.28
Step-by-step explanation:
