Convert 144 km/h to m/s
1 answer:
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As per Stefan - Boltzmann law we know that
1. Power radiated in the form of electromagnetic energy by an object at nonzero temperature.
2. Every object at absolute (kelvin) temperature t will radiate electromagnetic waves.
3. This radiation is typically in the infrared for objects at room temperature, with some visible light emitted for objects heated above 1000 k.
4. The formula governing the rate of energy radiation from a surface is given by ,
where p is the thermal power (also known as the heat current h).
Thermal radiation in visible light can be seen on hot metalwork. Its emission in the infrared is invisible to the human eye. Infrared cameras are capable of capturing this infrared emission.
Thermal radiation is electromagnetic radiation generated by the thermal motion of charged particles in matter. All matter with a temperature greater than absolute zero emits thermal radiation. Particle motion results in charge-acceleration or dipole oscillation which produce electromagnetic radiation.
Examples of thermal radiation include the visible light and infrared light emitted by an incandescent light bulb, the infrared radiation emitted by animals that is detectable with an infrared camera, and the cosmic microwave background radiation. Thermal radiation is different from thermal convection and thermal conduction—a person near a raging bonfire feels radiant heating from the fire, even if the surrounding air is very cold.
Sunlight is part of thermal radiation generated by the hot plasma of the Sun. The Earth also emits thermal radiation, but at a much lower intensity and different spectral distribution. The Earth's absorption of solar radiation, followed by its outgoing thermal radiation, are the two most important processes that determine the temperature and climate of the Earth in most climate models.
So the correct answer which is applicable here will be
This formula applies to any object of total surface area a, kelvin temperature t, and emissivity e
here
Answer:
Large binocular telescope, Keck 1 telescope, Hobby-Ebberly telescope, Subaru telescope, Gemini North telescope, Magellan 2 telescope
Explanation:
How much light a telescope can collect depends on its diameter, since in a bigger area more photons will be collected.
Remember that in a circle the area is defined as:
(1)
Where A is the area and r is its radius.
However, the radius can be determined by means of its diameter.
(1)
Where d is its diameter.
An example of this is when a person is collecting raindrops with a bucket and with a cup. Since the bucket has a bigger area than the cup, it will collect more raindrops by unit of time. In this scenario the raindrops represent the photons.
To determine the light collecting area of each telescope, equation 2 will be replaced in equation 1.
(3)
Case for Large binocular telescope:
For the second mirror will be the same value
Case for Keck 1 telescope:
Case for Hobby-Ebberly telescope:
Case for Subaru telescope:
Case for Gemini North telescope:
Case for Magellan 2 telescope:
Hence, they may be rank in the following way:
Large binocular telescope, Keck 1 telescope, Hobby-Ebberly telescope, Subaru telescope, Gemini North telescope, Magellan 2 telescope.
<em>Key term:</em>
<em>Photons: particles that constitute light. </em>
Answer:
(a) Time will be t = 3.56 sec
(b) Distance traveled by car when they are side by side is 37.38712 m
(b) Velocity of race car = 21.004 m/sec
velocity of stock car = 12.816 m/sec
Explanation:
We have given acceleration of the car
Acceleration of the stock car
When 1st car overtakes the second car then distance traveled by both the car will be same
(a) So
As both car starts from rest so initial velocity of both car will be 0 m/sec
It is given that stock car leaves 1 sec before
So
After solving t = 3.56 sec
(b) From second equation of motion
(c) From first equation pf motion v = u+at
So velocity of race car v = 0+5.9×3.56 = 21.004 m/sec
Velocity of stock car v = 0+ 3.6×3.56 = 12.816 m/sec