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3 years ago

10

If a Ferrari, with an initial velocity of 14m/s, accelerates at a rate of 60 m/s^2 for 4 seconds, what will its final velocity b

e

1 answer:

gtnhenbr [62]3 years ago

6 0

Answer:

254 m/s

Explanation:

(Vf-Vi) = at

(Vf-14)= 60 (4)

Vf = 254 m/s

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How is energy related to the change of state represent ed by the model

frozen [14]

Atoms gain energy as a solid changes to a liquid. If atoms energy during a change of state, they are pulled together by attractive forces and become more organized.

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4 years ago

A sound wave has a frequency of 776 Hz in air and a wavelength of 0.52 m. What is the temperature of the air? Relate the speed o

OLEGan [10]

Answer:

142.7650889

Explanation:

I think the answer above is correct. So to find the velocity of the wave you can do: frequency*wavelength = velocity

in your case, the velocity is equal to 403.5m/s

so we know that the 403.52 is the total velocity of the wave

and the equation: velocity at 0 degrees Celsius * $\sqrt{{T}/{273}}$ where T represents temperature in Kelvins = veloctity

so we set 403.52 = 327* $\sqrt{{T}/{273}}$ and solve for T

T will then equal the degree in Kelvins

so to convert from Kelvins to degrees celsius you subtract 273 from the Kelvins value and you are left with the degrees in Celsius which equals 142.7650889 degrees Celsius

5 0

3 years ago

Suppose that while moving into an apartment you move a refrigerator into place by sliding it across the ﬂoor. The refrigerator w

sweet-ann [11.9K]

Answer:

358 N

Explanation:

$F=\mu N$ where F is the force, $\mu$ is the coefficient of static friction between the ﬂoor and the refrigerator and N is the weight

Normally, N=mg hence $F=\mu mg$ where m is the mass of object and g is the acceleration due to gravity

In this case, N is given as 895 N and the coefﬁcient of static friction between the ﬂoor and the refrigerator is 0.400 hence substituting them in the formula we obtain

$F=\mu N= 0.4\times 895 N= 358 N$

4 0

4 years ago

A hollow, conducting sphere with an outer radius of 0.250 m and an inner radius of 0.200 m has a uniform surface charge density

frez [133]

Answer: a)5.73 *10^-6 C/m^2; b)648*10· N/C c)56.5 *10^3 Nm^2/C

Explanation: Considering the definition of surface charge density as:

σ = Q/ area of sphere

so Q = σ * 4*π* R^2outer

The new Q at the outer radius is: Q initial -0.5 microC =5 micro C

The Electric with the new outer charge is equal to:

E= k*Q / R^2outer= 9 10^9* 5 microC/(0.25m)^2= 648*10^3 N/C

Finally the flux corresponding to the internal charge is equal to

By using Gauss law, the total flux is equal to net change divided ε0

so this is 0.5 microC/ ε0= 56.5 *10^3 Nm^2/C

5 0

4 years ago

When a car's starter is in use, it draws a large current. The car's lights draw much less current. As a certain car is starting,

ad-work [718]

Answer:

EMF = 11.35 V

R = 0.031Ω

Explanation:

To find the battery's EMF and the internal resistance we need to use Ohm's law:

$V = IR$

Where:

V: is the voltage

I: is the current

R is the resistance

We have:

The current through the battery is 64.2 A and the potential difference across the battery terminals is 9.36 V:

$\epsilon = V + IR$

$\epsilon = 9.36 V + 64.2A*R$ (1)

When only the car's lights are used, the current through the battery is 1.96 A and the terminal potential difference is 11.3 V:

$\epsilon = 11.3 V + 1.96A*R$ (2)

By solving equation (1) and (2) for R we have:

$9.36 V + 64.2A*R = 11.3 V + 1.96A*R$

$R = \frac{1.94 V}{62.24A} = 0.031 \Omega$

Hence, the internal resistance is 0.031 Ω.

Now, by entering R into equation (1) we can find the battery's EMF:

$\epsilon = 9.36 V + 64.2A*0.031 \Omega$

$\epsilon = 11.35 V$

Therefore, the battery's EMF is 11.35 V.

I hope it helps you!

8 0

4 years ago