Answer:
The average power the student expended to overcome gravity is 560W, Watts is a units of work it is Joules /time or kg*
/ ![s^{3}](https://tex.z-dn.net/?f=s%5E%7B3%7D)
Explanation:
Weight = 700N
![F= m*g*h \\m*g= 700N\\F= 700N*h\\F=700N*8m\\F= 5600 N*m \\F=5600 J](https://tex.z-dn.net/?f=F%3D%20m%2Ag%2Ah%20%5C%5Cm%2Ag%3D%20700N%5C%5CF%3D%20700N%2Ah%5C%5CF%3D700N%2A8m%5C%5CF%3D%205600%20N%2Am%20%5C%5CF%3D5600%20J)
The power is the work in (Joules) or (N*m) in a determinate time (s) to get Watts (W) units for work
![Work= \frac{5600 J}{10s} = \frac{5600 \frac{kg*m^{2} }{s^{2} } }{10 s} \\Work= 560\frac{kg*m^{2} }{s^{3} } \\Work =560 W](https://tex.z-dn.net/?f=Work%3D%20%5Cfrac%7B5600%20J%7D%7B10s%7D%20%3D%20%5Cfrac%7B5600%20%5Cfrac%7Bkg%2Am%5E%7B2%7D%20%7D%7Bs%5E%7B2%7D%20%7D%20%7D%7B10%20s%7D%20%20%5C%5CWork%3D%20560%5Cfrac%7Bkg%2Am%5E%7B2%7D%20%7D%7Bs%5E%7B3%7D%20%7D%20%5C%5CWork%20%3D560%20W)
If the object's kinetic energy is zero, then due to in multiplication factor, it's momentum will also be equal to zero 'cause the velocity of the object must be Nil
In short, Your Answer would be: "Zero"
Hope this helps!
Answer:
Yes
Explanation:
When an object has more mass it takes more gravity to keep it down therefore producing friction which in return reduces the amount of kinetic energy created. A change in an object's speed has an greater effect on its kinetic energy. than a change in its mass has, because kinetic energy is proportional to.
Answer:
You didn't give the information needed for the answer bud
Explanation: