Answer:
Your answer is c
Step-by-step explanation:
the two inequalities are x =< 1 and x =>2 which is shown by the number line in option c
The graph is the horizontal line:
y=3 it has a slope of zero.
Function 2 is
y=3x+1, it is in slope-intercept form, y=mx+b where m is the slope and b is the y=intercept so in this case it has a slope of 3.
So the difference in slopes is 3-0=3
Answer:
122*
122 degrees
Step-by-step explanation:
m∠GEF is 13 less than 5 times m∠DEG and m∠DEF = 149*
Solution:
As per given data,
m∠GEF = 5m∠DEG - 13* … (i)
m∠DEF = 149* -> m∠GEF + m∠DEG = 149* .. (ii)
Substituting value of m∠GEF in (ii)
We get,
(5m ∠DEG - 13*) + m∠DEG = 149*
6m ∠DEG - 13* = 149*
6m ∠DEG = 149* + 13* = 162*
m∠DEG = * = 27*
Substituting value of m∠DEG in (i)
We get,
m∠GEF = 5(27*) - 13*
m∠GEF = 135* - 13* = 122*
The general vertex form is this:
v(x) = a (x-h)2 + k
where (h,k) is the coordinates of the of vertex.
and a indicates the widening or shrinking of the function compared to another parabolic function. If a become bigger, the graph becomes narrower. If a becomes negative, the graph is reflected over the x-axis.
Comparing f(x) = x2 with g(x) = -3(x+6)2 + 48, we have the following transformations:
The graph is reflected over the x-axis
The graph is made narrower.
The graph is shifted 6 units to the left.
The graph is shifted 48 units up.
From the choices we only have:
<span>The graph of f(x) = x2 is made narrower</span>
