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2 years ago

6

Simplify the expression. Thanks yall, I'll give brainliest to the right answer

1 answer:

Alik [6]2 years ago

3 0

Answer:

ok.

Step-by-step explanation:

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The area of a rectangular wall of a barn is 40 square feet. Its length is 6 feet longer than the width. Find the length and widt

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Length is 10 and width is 4

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3 years ago

An insurance company offers its policyholders a number of different premium payment options. For a randomly selected policyholde

n200080 [17]

Answer:

(a)

$\begin{array}{cccccc}x & {1} & {3} & {4} & {6} & {12} \ \\ P(x) & {0.30} & {0.10} & {0.05} & {0.15} & {0.40} \ \end{array}$

(b)

$P(3 \le x \le 6) = 0.30$

$P(4 \le x)=0.60$

Step-by-step explanation:

Given

$F(x) = \left[\begin{array}{ccc}0& x$

Solving (a): The pmf

This means that we list out the probability of each value of x.

To do this, we simply subtract the current probability value from the next.

So, we have:

$\begin{array}{cccccc}x & {1} & {3} & {4} & {6} & {12} \ \\ P(x) & {0.30} & {0.10} & {0.05} & {0.15} & {0.40} \ \end{array}$

The calculation is as follows:

$0.30 - 0 = 0.30$

$0.40 - 0.30 = 0.10$

$0.45 - 0.40 = 0.05$

$0.60 - 0.45 = 0.15$

$1 - 0.60 = 0.40$

The x values are gotten by considering where the equality sign is in each range.

$1 \le x < 3$ means $x = 1$

$3 \le x < 4$ means $x = 3$

$4 \le x < 6$ means $x=4$

$6 \le x < 12$ means $x = 6$

$12 \le x$ means $x = 12$

Solving (b):

$(i)\ P(3 \le x \le 6)$

This is calculated as:

$P(3 \le x \le 6) = F(6) - F(3-)$

From the given function

$F(6)= 0.60$

$F(3-) = F(1) = 0.30$

So:

$P(3 \le x \le 6) = 0.60 - 0.30$

$P(3 \le x \le 6) = 0.30$

$(ii)\ P(4 \le x)$

This is calculated as:

$P(4 \le x)=1 - F(4-)$

$P(4 \le x)=1 - F(3)$

$P(4 \le x)=1 - 0.40$

$P(4 \le x)=0.60$

8 0

2 years ago

Please answer the question on the picture

Ilya [14]

The answer is the first option

5 0

3 years ago

Read 2 more answers

A sample of 20 account balances of a credit company showed an average balance of $1,170 and a standard deviation of $125. You wa

Lady_Fox [76]

Answer:

The P-value for this test is P=0.2415.

Step-by-step explanation:

We have to perform an hypothesis testing on the mean of alla account balances.

The claim is that the mean of all account balances is significantly greater than $1,150.

Then, the null and alternative hypothesis are:

$H_0: \mu=1150\\\\H_a: \mu>1150$

The sample size is n=20, with a sample mean is 110 and standard deviation is 125.

We can calculate the t-statistic as:

$t=\dfrac{\bar x-\mu}{s/\sqrt{n}}=\dfrac{1170-1150}{125/\sqrt{20}}=\dfrac{20}{27.95}=0.7156$

The degrees of freedom fot this test are:

$df=n-1=20-1=19$

For this one-tailed test and 19 degrees of freedom, the P-value is:

$P-value=P(t>0.7156)=0.2415$

8 0

3 years ago

8) 4 16<br> Long division

tamaranim1 [39]

Answer:

Here you go now

0.25

or

1/4

Step-by-step explanation:

Hopefully this is correct!

- Unbrand -

3 0

2 years ago

Read 2 more answers