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Verdich [7]
3 years ago
10

Draw a rectangular prism with length 8 feet, width 5 feet, and height 3 1/2 feet. Imagine this rectangular prism is full of wate

r. Now draw a second rectangular prism with length 26 feet, width 10 feet, and height 4 feet. If you poured all the water from the first rectangular prism into the second, how high would the water be?
Mathematics
1 answer:
Alexandra [31]3 years ago
7 0

Answer:

the water will be 0.538 feet high

Step-by-step explanation:

Once the rectangles have been sketched out, with their correct dimensions, we will notice that the quantity of water that will fill the first rectangular prism simply equals to its volume.

The volume of the rectangular prism can be obtained by using the formula:

length X breadth X height.

First Prism:

Volume of the first prism =  8 X 5 X 3.5 = 140 square feet.

Second Prism

The same volume of water was poured into the second prism which had a different dimension from the first. To calculate the new height, we will use the fact that the volume = base area X height.

hence height = volume / base area

height of water = 140 / (26 X 10 ) = 0.538 feet

Therefore, the water will be 0.538 feet high

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42

Step-by-step explanation:

so you do 7 times 6 and you should get 42

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3 years ago
An ice cream store has the pricing shown below. You want to determine the best value. The height of the cone is 4.5 in and the d
nignag [31]

Solution:

Step 1:

We will calculate the volume of ice cream in the single scoop

The volume of the ice cream will be

\begin{gathered} V=\frac{1}{3}\pi r^2h+\frac{2}{3}\pi r^3 \\ r=\frac{2in}{2}=1in(cone) \\ h=4.5in \\ r=\frac{3in}{2}=1.5in(radius\text{ of the hemisphere\rparen} \end{gathered}

By substituting the values, we will have

\begin{gathered} V=\frac{1}{3}\pi r^{2}h+\frac{2}{3}\pi r^{3} \\ V=\frac{1}{3}\times\frac{22}{7}\times1^2\times4.5+\frac{2}{3}\times\frac{22}{7}\times1.5^3 \\ V=\frac{33}{7}+\frac{99}{14} \\ V=\frac{165}{14} \\ V=11.79in^3 \end{gathered}

Step 2:

We will use the formula below to calculate the volume of the two scoops of ic cream

\begin{gathered} V=\frac{1}{3}\pi r^2h+\frac{4}{3}\pi r^3 \\ V=\frac{1}{3}\times\frac{22}{7}\times1^2\times4.5in+\frac{4}{3}\times\frac{22}{7}\times1.5^3 \\ V=\frac{33}{7}+\frac{99}{7} \\ V=\frac{132}{7} \\ V=18.86in^3 \end{gathered}

Step 3:

We will use the formula below to calculate the volume of the three scoops of ic cream

\begin{gathered} V=\frac{1}{3}\pi r^2h+\frac{6}{3}\pi r^3 \\ V=\frac{1}{3}\times\frac{22}{7}\times1^2\times4.5+2\times\frac{22}{7}\times1.5^3 \\ V=\frac{33}{7}+\frac{297}{14} \\ V=\frac{363}{14} \\ V=25.93in^3 \end{gathered}

For the first ice cream with one scoop

\begin{gathered} 1in^3=\frac{3.50}{11.79} \\ 1in^3=\text{ \$}0.30 \end{gathered}

For the second ice cream with two scoops

\begin{gathered} 1in^3=\frac{4.50}{18.86} \\ 1in^3=\text{ \$}0.24 \end{gathered}

For the third ice cream with three scoops

\begin{gathered} 1in^3=\frac{5.50}{25.93} \\ 1in^3=\text{ \$}0.21 \end{gathered}

Hence,

The final answer is

The triple sold at $5.50 has the best value because it has the lowest price of $0.21 per cubic inch of the ice cream

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Step-by-step explanation:

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An electrician leans an extension ladder against the outside wall of a house so that it reaches an electric box 22 feet up. The
jeka57 [31]

The ladder and the outside wall form a right triangle

The length of the ladder is 97.8 feet

<h3>How to determine the length of the ladder?</h3>

The given parameters are:

Distance (B) = 22 feet

Angle of elevation (θ) = 77 degrees

The length (L) of the ladder is calculated using the following cosine ratio

cos(θ) = B/L

So, we have:

cos(77) = 22/L

Make L the subject

L = 22/cos(77)

Evaluate the product

L = 97.8

Hence, the length of the ladder is 97.8 feet

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