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3 years ago

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The voltage in a circuit is the product of two factors, the resistance and the current. If the voltage is 6ir + 15i + 8r+20, fin

d the expressions for the current and resistance

1 answer:

zhuklara [117]3 years ago

6 0

Answer:

resistance: (2r +5)
current: (3i +4)

Step-by-step explanation:

The factors of the given expression are ...

6ir +15i +8r +20 = (3i +4)(2r +5)

Which factor is current and which is resistance is not clear. Usually, resistance is referred to using the variable r, so we suppose the expressions are supposed to be ...

resistance: (2r +5)

current: (3i +4)

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The population of a colony of bacteria can be modeled by the function P(t) = 19,300(5)^t, where t is the elapsed time

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Answer: root t(5)/19300

Explanation:

P(t) = 19300(5)^t
P-1(t) = root t(5)/19300

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We have two fractions, 3/4 and 7/6 , and we want to rewrite them so that they have a common denominator (and whole number numera

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Answer:

12,24 etc

Step-by-step explanation:

4 and 6 both go into 12 evenly

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We could also use 24

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3 years ago

Match the type of graph with its description.

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Caitlin says the difference in their ages is 24 years. In two or more complete sentences, explain whether or not Caitlin is corr

Paraphin [41]

~Hello There!~

$\frac{m}{s} =\frac{2}{5}$

Rearrange for s

$s = \frac{5m}{2}$

After 8 years, the new equation would be:

$\frac{m+8}{s+8} =\frac{1}{2}$

Cross multiply

$2m+16 = s+8$

Subtract 8

$2m+8=s$

Substitute old equation

$2m+8 = \frac{5m}{2}$

Solve to get m as 16.

s = 40.

Their current ages are 16 and 40 and the different is 24 years. Therefore, Caitlin is correct.

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3 years ago

Graph a parabola whose x-intercepts are at x=-3 and x=5 and whose minimum value is y=-4

docker41 [41]

Answer:

(See explanation for further details)

Step-by-step explanation:

The standard equation of the parabola is:

$y + 4 = C \cdot (x-k)^{2}$

The formula is now expanded into a the form of a second-order polynomial:

$y + 4 = C\cdot x^{2} -2\cdot C\cdot k \cdot x +C\cdot k^{2}$

$y = C\cdot x^{2} - (2\cdot C \cdot k) \cdot x + (C\cdot k^{2}-4)$

The general equation of the second-order polynomial is:

$x = \frac{2\cdot C \cdot k \pm \sqrt{4\cdot C^{2}\cdot k^{2}-4\cdot C\cdot (C\cdot k^{2}-4)}}{2\cdot C}$

$x = k \pm \frac{\sqrt{C^{2}\cdot k^{2}-C^{2}\cdot k^{2}+4\cdot C}}{C}$

$x = k \pm 2\cdot \frac{\sqrt{C}}{C}$

$x = k \pm \frac{2}{\sqrt{C}}$

The equations to be solved are presented herein:

$-3 = k -\frac{2}{\sqrt{C}}$

$5 = k + \frac{2}{\sqrt{C}}$

Now, the solution of the system is:

$-3 +\frac{2}{\sqrt{C}} = 5 -\frac{2}{\sqrt{C}}$

$\frac{4}{\sqrt{C}} = 8$

$\sqrt{C} = \frac{1}{2}$

$C = \frac{1}{4}$

$k = 5 - \frac{2}{\sqrt{\frac{1}{4} }}$

$k = 1$

The equation of the parabola is:

$y = \frac{1}{4}\cdot (x-1)^{2} -4$

Lastly, the graphic of the function is included as attachment.

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3 years ago