Answer: 6
Step-by-step explanation:
1 2/10 x 5=6 hope this helps
The probability of event A and B to both occur is denoted as P(A ∩ B) = P(A) P(B|A). It is the probability that Event A occurs times the probability that Event B occurs, given that Event A has occurred.
So, to find the probability that you will be assigned a poem by Shakespeare and by Tennyson, let Event A = the event that a Shakespeare poem will be assigned to you; and let Event B = the event that the second poem that will be assigned to you will be by Tennyson.
At first, there are a total of 13 poems that would be randomly assigned in your class. There are 4 poems by Shakespeare, thus P(A) is 4/13.
After the first selection, there would be 13 poems left. Therefore, P(B|A) = 2/12
Based on the rule of multiplication,
P(A ∩ B) = P(A) P(B|A)P(A ∩ B) = 4/13 * 2/12
P(A ∩ B) = 8/156
P(A ∩ B) = 2/39
The probability that you will be assigned a poem by Shakespeare, then a poem by Tennyson is 2/39 or 5.13%.
Answer:
x = 1/3
Step-by-step explanation:
-4(3x − 2) = 6x + 2
Distribute
-12x +8 = 6x +2
Add 12x to each side
12x-12x+8 = 6x+2+12x
8 = 18x+2
Subtract 2 from each side
8-2 = 18x+2-2
6 = 18x
Divide each side by 18
6/18 = 18x/18
1/3 =x
The answer than you are looking for is 53.84
