1) given function
y = - 2 ^ ( -x + 2) + 1
2) domain: domain is the set of the x-values for which the function is defined.
The exponential function is defined for all the real numbers, so the domain of the given function is all the real numbers.
3) x-intercept => y = 0
=> y = - 2 ^ ( -x + 2) + 1 = 0 => 2^ ( -x + 2) = 1
=> - x + 2 = 0 => x = 2
The x-intercept is x = 0
4) y-intercept => x = 0
=> y = - 2 ^ ( -x + 2) + 1= - 2 ^ ( 0 + 2) 1 = - (2)^(2) + 1 =- 4 + 1 = - 3
=> The y-intercept is - 3
5) limit when x -> negative infinite
Lim f(x) when x -> ∞ = - ∞
6) limit when x -> infinite
Lim f(x) when x - > infinite = 1
=> asymptote = y = 1
7) range is the set of values of the fucntion: y
Given that the function is strictly decreasing from -∞ to ∞, the range is from - ∞ to less than 1
Range (-∞,1)
Answer: False
Step-by-step explanation:
degrees of freedom=(r-1)(c-1)
I don't know if I'm exactly right
if not sorry
Reduce a 24 cm by 36 cm photo to 3/4 original size.
The most logical way to do this is to keep the width-to-height ratio the same: It is 24/36, or 2/3. The original photo has an area of (24 cm)(36 cm) = 864 cm^2.
Let's reduce that to 3/4 size: Mult. 864 cm^2 by (3/4). Result: 648 cm^2.
We need to find new L and new W such that W/L = 2/3 and WL = 648 cm^2.
From the first equation we get W = 2L/3. Thus, WL = 648 cm^2 = (2L/3)(L).
Solve this last equation for L^2, and then for L:
2L^2/3 = 648, or (2/3)L^2 = 648. Thus, L^2 = (3/2)(648 cm^2) = 972 cm^2.
Taking the sqrt of both sides, L = + 31.18 cm. Then W must be 2/3 of that, or W = 20.78 cm.
Check: is LW = (3/4) of the original 864 cm^2? YES.
