Answer:
The length of the diagonal HJ is 10.82 units
Step-by-step explanation:
* Lets revise the rule of the distance between two points
- 
, where
and 
are the two points
* Lets use this rule to find the length of the diagonal HJ
∵ The coordinates of point H are (-4 , 3)
∵ The coordinates of point J are (5 , -3)
∴ 
and 
∴ 
and 
- Lets find the length of the diagonal HJ by using the rule above
∴ HJ = 
∴ HJ = 
∴ HJ = 10.82
* The length of the diagonal HJ is 10.82 units
Answer:
The first piece is 5 inches long, while the second is 15 inches and the third one is 20 inches.
Step-by-step explanation:
To determine the length of the 3 pieces, knowing that the total of the board is 40 inches, and that the second measures 3 times more than the first and the third measures 4 times more than the first, the following equation must be performed:
X + 3X + 4X = 40
8X = 40
X = 40/8
X = 5
Therefore, the first piece is 5 inches long, while the second is 15 inches and the third 20 inches.
Answer:
(15,18)
Step-by-step explanation:
write two equations with the information provided.
2x + 3y = 84
x + 4y = 87
use the property of substitution to answer.
x + 4y = 87, x = 87 - 4y
2(87 - 4y) + 3y = 84
174 - 8y + 3y = 84
174 - 84 = 8y - 3y
90 = 5y
90/5 = y
y = 18
Add the value of Y to an original equation. Solve for X
2x + 3(18) = 84
2x + 54 = 84
2x = 84 - 54
2x = 30
x = 30/2
x = 15
Answer:
Step-by-step explanation:
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