1,520
add 1,500 plus 15 plus 5
Im in your class at school im kayla
Answer:
a = -0.3575
Step-by-step explanation:
The points A and D lie on the x-axis, this means that they are the x-intercepts of the parabola, and therefore we can find their location.
The points A and B are located where
![y=a(x+1)(x-5)=0](https://tex.z-dn.net/?f=y%3Da%28x%2B1%29%28x-5%29%3D0)
This gives
![x=-1](https://tex.z-dn.net/?f=x%3D-1)
![y=5](https://tex.z-dn.net/?f=y%3D5)
Now given the coordinates of A, we are in position to find the coordinates of the point B. Point B must have y coordinate of y=2 (because the base of the trapezoid is at y=0), and the x coordinate of B, looking at the figure, must be x coordinate of A plus horizontal distance between A and B, i.e
![B_x=A_x+\frac{2}{tan(60)} =-1+\frac{2\sqrt{3} }{3}](https://tex.z-dn.net/?f=B_x%3DA_x%2B%5Cfrac%7B2%7D%7Btan%2860%29%7D%20%3D-1%2B%5Cfrac%7B2%5Csqrt%7B3%7D%20%7D%7B3%7D)
Thus the coordinates of B are:
![B=(-1+\frac{2\sqrt{3} }{3},2)](https://tex.z-dn.net/?f=B%3D%28-1%2B%5Cfrac%7B2%5Csqrt%7B3%7D%20%7D%7B3%7D%2C2%29)
Now this point B lies on the parabola, and therefore it must satisfy the equation ![y=a(x+1)(x-5).](https://tex.z-dn.net/?f=y%3Da%28x%2B1%29%28x-5%29.)
Thus
![2=a((-1+\frac{2\sqrt{3} }{3})+1)((-1+\frac{2\sqrt{3} }{3})-5)](https://tex.z-dn.net/?f=2%3Da%28%28-1%2B%5Cfrac%7B2%5Csqrt%7B3%7D%20%7D%7B3%7D%29%2B1%29%28%28-1%2B%5Cfrac%7B2%5Csqrt%7B3%7D%20%7D%7B3%7D%29-5%29)
Therefore
![a=\frac{2}{((-1+\frac{2\sqrt{3} }{3})+1)((-1+\frac{2\sqrt{3} }{3})-5)}](https://tex.z-dn.net/?f=a%3D%5Cfrac%7B2%7D%7B%28%28-1%2B%5Cfrac%7B2%5Csqrt%7B3%7D%20%7D%7B3%7D%29%2B1%29%28%28-1%2B%5Cfrac%7B2%5Csqrt%7B3%7D%20%7D%7B3%7D%29-5%29%7D)
![\boxed{a=-0.3575}](https://tex.z-dn.net/?f=%5Cboxed%7Ba%3D-0.3575%7D)
Answer:
14 b^5
Step-by-step explanation:
you can do all mathmatical operations to same variables with same power
i believe it’s D because where you have 20 marked it’s 20 more from where you are which would be around 40 which is why i’m saying D