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3 years ago

There is a total of 45 boys and girls in a choir.

Mathematics

2 answers:

GuDViN [60]3 years ago

4 0

Answer:

The mean age of all 45 boys and girls is 16.5years

Step-by-step explanation:

Since the mean age of the 18 boys is 16.2years,

∴ Sum of their ages = 18 × 16.2

= 291.6years

The mean age of the 27 girls is 16.7years

∴ Sum of their ages = 27 × 16.7

= 450.9years

∴ Mean age of all 45 boys and girls = $\frac{291.6 + 450.9}{45}$ years

= $\frac{742.5}{45}$ years

= 16.5 years

∴ The mean age of all 45 boys and girls is 16.5 years.

rusak2 [61]3 years ago

3 0

Answer:

16.5 year

Step-by-step explanation:

Using, mean = sum/no. *of observations

Here,

=> 16.2 = (sum of ages of boys)/18

=> 16.2 x 18 = sum of ages of boys

=> 291.6 = sum of ages of boys

Similarly, sum of ages of girls = 27 x 16.7 = 450.9

Mean(total) = (sumof agesof boys + girls)/45

Mean = (291.6 + 450.9)/45 = 16.5

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