All categories

2 years ago

Please help me not hard please

Mathematics

1 answer:

IrinaVladis [17]2 years ago

8 0

Answer:

I think it's A

Step-by-step explanation:

You might be interested in

Please help me solve this problem ASAP

Andru [333]

Quadrant 4
Hope this helps!

4 0

2 years ago

15 pts! Will Give Brainliest Halp! PLZ

aivan3 [116]

Theres a saying: Dividing fractions dont ask why, just flip the second and multiply.

so a/b / c/d = a/b * d/c

-8/2 * -3/6

1. cross - cancel common factor 2

4/2 * -3/3

2. Multiply

-4(-3)/ 2*3

3. multiply numbers

--12/2*3

- -12/6

4. Apply fraction rule -a/b=- a/b

=-(-12/6)

5. divide

= -(-2)

6. Apply rule -(-a)=a

Your answer would be 2

3 0

3 years ago

Read 2 more answers

Can someone please help me arrange this in order.

Nesterboy [21]

Is this ELA because if it is i am horrible at it

7 0

3 years ago

Does anyone know the the answer to the second algebra question? Will give brainiest

astraxan [27]

Answer:

$\sqrt[3]{x^{10} }[\tex]Step-by-step explanation:Exponential Rules:[tex]x^{a} + x^{b} = x^{a + b}$

$\sqrt[b]{x^{a} } =x^{\frac{a}{b} } Original Equation:[tex]\sqrt[3]{x^{10} } = x^{\frac{10}{3} } Answer:[tex]\sqrt[3]{x^{10} }[\tex]Convert the cubed root to a power. Cubed root = [tex]\frac{1}{3}$

$x^{3} x^{\frac{1}{3} }$

Convert them, so they have a common denominator - $\frac{1}{3}$

$\frac{3}{1} * \frac{1}{3}= \frac{9}{3}$

$\frac{9}{3} + \frac{1}{3} = \frac{10}{3}$

[tex]\sqrt[3]{x^{10} }[\tex] = [tex]x^{\frac{10}{3} } [\tex]

8 0

2 years ago

Use properties to find the sum or product 93 + (68+7)

-BARSIC- [3]

Use PEMDAS, Parenthesis and Exponents, then Multiplication and Division, then Addition and Subtraction, all from left to right in the line. So 68+7=75, and 93+75=168

6 0

2 years ago

Read 2 more answers