Answer:

Step-by-step explanation:
we are given half-life of PO-210 and the initial mass
we want to figure out the remaining mass <u>after</u><u> </u><u>4</u><u>2</u><u>0</u><u> </u><u>days</u><u> </u>
in order to solve so we can consider the half-life formula given by

where:
- f(t) is the remaining quantity of a substance after time t has elapsed.
- a is the initial quantity of this substance.
- T is the half-life
since it halves every 140 days our T is 140 and t is 420. as the initial mass of the sample is 5 our a is 5
thus substitute:

reduce fraction:

By using calculator we acquire:

hence, the remaining sample after 420 days is 0.625 kg
6 / 1/2
that's 6 * 2
There are 12 meals in a bag of dog food
Answer:
im 70% sure that its D
Step-by-step explanation:
I hope i helped sorry if im wrong :D
Answer:
2x squared +1 (-)x squared -7 is
a.) x squared +8
Step-by-step explanation:
:)
Swap x and y, f^-1 is and solve for y to get f^-1 the inverse of f. f(f^-1)=f^-1(f)=x is the identity as a check
f(2)=3*2+1=7 (2,7)
f^-1(7)=2 (7,2)