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Ad libitum [116K]

3 years ago

13

Plz can someone help me with number 5?

1 answer:

Anettt [7]3 years ago

7 0

Answer:

77

Step-by-step explanation:Trust

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Use the slope formula to find the slope between the given two points <br><br> (-4, -1) and (-2, -5)

OlgaM077 [116]

Answer:

-2

Step-by-step explanation:

use the slope formula which is y2-21/x2-x1

these are what i chose my numbers to be

-4=x1

-1= y1

-2= x2

-5= y2

-5-(-1)/-2-(-4) = -2

thats all

3 0

3 years ago

A container can hold quarts of 8 3/5cooking oil. It contains 1 1/3 quarts of cooking oil. How much more cooking oil is needed to

Mamont248 [21]

Answer:

4 14/15

Step-by-step explanation:

8 3/5 - 11/3

8 9/15 - 55/15

8 9/15 - 3 10/15

7 24/15 - 3 10/15

4 14/15

6 0

3 years ago

Which of the following CANNOT be given the lengths of the sides of a triangle?

Katena32 [7]

The sides of a triangle must satisfy the triangle inequality, which states the sum of the lengths of any two sides is strictly greater than the length of the remaining side.

We really only have to check if the sum of the two smaller sides exceeds the largest side.

A. 5+6>7, ok

B. 6+6>10, ok

C. 7+7=14 Not ok, this is a degenerate triangle not a real triangle

D. 4+6>8 ok

Answer: C

6 0

3 years ago

Read 2 more answers

A circus tent is cylindrical upto a height of 3.3 m and conical above it if the diameter of the base is 100m and slant height of

Rina8888 [55]

Total cost of canvas required in making the tent is rupees 79128

<em><u>Solution: </u></em>

Given:

Height of the cylindrical tent = h = 3.3 m

Diameter of it's base = d = 100m

$radius = \frac{diameter}{2} = \frac{100}{2} = 50$

r = 50 m

<em><u>Curved surface area of cylinder:</u></em>

$C.S.A = 2 \pi rh$

$C.S.A = 2 \times 3.14 \times 50 \times 3.3 = 1036.2$

Thus Curved surface area of cylinder = 1036.2 square meter

<em><u>Curved surface area of cone:</u></em>

$C.S.A = \pi rl$

$C.S.A = 3.14 \times 50 \times 56.4 = 8854.8$

Thus Curved surface area of cone = 8854.8 square meter

<em><u>Total curved area of tent:</u></em>

⇒ curved area of cone + curved area of cylinder

$\rightarrow 8854.8 + 1036.2=9891$

Thus total curved area of tent = 9891 square meter

<em><u>find total cost of canvas required in making the tent:</u></em>

The cost of canvas is 8 rupees per square meter

$\rightarrow \text{total cost } = 9891 \times 8 = 79128$

Thus total cost of canvas required in making the tent is rupees 79128

7 0

3 years ago

Determine formula of the nth term 2, 6, 12 20 30,42

nalin [4]

Check the forward differences of the sequence.

If $\{a_n\} = \{2,6,12,20,30,42,\ldots\}$ , then let $\{b_n\}$ be the sequence of first-order differences of $\{a_n\}$ . That is, for n ≥ 1,

$b_n = a_{n+1} - a_n$

so that $\{b_n\} = \{4, 6, 8, 10, 12, \ldots\}$ .

Let $\{c_n\}$ be the sequence of differences of $\{b_n\}$ ,

$c_n = b_{n+1} - b_n$

and we see that this is a constant sequence, $\{c_n\} = \{2, 2, 2, 2, \ldots\}$ . In other words, $\{b_n\}$ is an arithmetic sequence with common difference between terms of 2. That is,

$2 = b_{n+1} - b_n \implies b_{n+1} = b_n + 2$

and we can solve for $b_n$ in terms of $b_1=4$ :

$b_{n+1} = b_n + 2$

$b_{n+1} = (b_{n-1}+2) + 2 = b_{n-1} + 2\times2$

$b_{n+1} = (b_{n-2}+2) + 2\times2 = b_{n-2} + 3\times2$

and so on down to

$b_{n+1} = b_1 + 2n \implies b_{n+1} = 2n + 4 \implies b_n = 2(n-1)+4 = 2(n + 1)$

We solve for $a_n$ in the same way.

$2(n+1) = a_{n+1} - a_n \implies a_{n+1} = a_n + 2(n + 1)$

Then

$a_{n+1} = (a_{n-1} + 2n) + 2(n+1) \\ ~~~~~~~= a_{n-1} + 2 ((n+1) + n)$

$a_{n+1} = (a_{n-2} + 2(n-1)) + 2((n+1)+n) \\ ~~~~~~~ = a_{n-2} + 2 ((n+1) + n + (n-1))$

$a_{n+1} = (a_{n-3} + 2(n-2)) + 2((n+1)+n+(n-1)) \\ ~~~~~~~= a_{n-3} + 2 ((n+1) + n + (n-1) + (n-2))$

and so on down to

$a_{n+1} = a_1 + 2 \displaystyle \sum_{k=2}^{n+1} k = 2 + 2 \times \frac{n(n+3)}2$

$\implies a_{n+1} = n^2 + 3n + 2 \implies \boxed{a_n = n^2 + n}$

6 0

2 years ago