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inn [45]
3 years ago
6

Which of these sets of ordered pairs would define a line with a negative slope?

Mathematics
2 answers:
grin007 [14]3 years ago
7 0

Answer:

C.

Step-by-step explanation:

Formula for finding slope with no graph: <u>y2 - y1</u>

x2 - x1

Now substitute each of the coordinates to its corresponding variables.

Remember: (x, y)

tatiyna3 years ago
7 0

Answer:

C (3, 6) and (5, 1)

Step-by-step explanation:

I just took the test and its right, also if you follow the steps on how to solve these, you will get your answer.

The steps are

y2 - y1  

x2 - x1

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strojnjashka [21]

Answer:https://worthstart.com/stage-names/
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Step-by-step explanation:

7 0
2 years ago
The probability that a randomly selected 3-year-old male chipmunk will live to be 4 years old is 0.96516.
mezya [45]

Using the binomial distribution, it is found that there is a:

a) The probability that two randomly selected 3-year-old male chipmunks will live to be 4 years old is 0.93153 = 93.153%.

b) The probability that six randomly selected 3-year-old male chipmunks will live to be 4 years old is 0.80834 = 80.834%.

c) The probability that at least one of six randomly selected 3-year-old male chipmunks will not live to be 4 years old is 0.19166 = 19.166%. This probability is not unusual, as it is greater than 5%.

-----------

For each chipmunk, there are only two possible outcomes. Either they will live to be 4 years old, or they will not. The probability of a chipmunk living is independent of any other chipmunk, which means that the binomial distribution is used to solve this question.

Binomial probability distribution  

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

In this problem:

  • 0.96516 probability of a chipmunk living through the year, thus p = 0.96516

Item a:

  • Two is P(X = 2) when n = 2, thus:

P(X = 2) = C_{2,2}(0.96516)^2(1-0.96516)^{0} = 0.9315

The probability that two randomly selected 3-year-old male chipmunks will live to be 4 years old is 0.93153 = 93.153%.

Item b:

  • Six is P(X = 6) when n = 6, then:

P(X = 6) = C_{6,6}(0.96516)^6(1-0.96516)^{0} = 0.80834

The probability that six randomly selected 3-year-old male chipmunks will live to be 4 years old is 0.80834 = 80.834%.

Item c:

  • At least one not living is:

P(X < 6) = 1 - P(X = 6) = 1 - 0.80834 = 0.19166

The probability that at least one of six randomly selected 3-year-old male chipmunks will not live to be 4 years old is 0.19166 = 19.166%. This probability is not unusual, as it is greater than 5%.

A similar problem is given at brainly.com/question/24756209

6 0
2 years ago
Which of the following represents<br> this statement? |3x – 41 &lt; 2
agasfer [191]
<h2>Answer:</h2><h2>D is the correct answer </h2><h2></h2><h2>Hope this helps!!</h2>

3 0
3 years ago
I have 7 hundreds blocks, 5 tens blocks, and 8 ones blocks. I use my blocks to model two 3-digit numbers. What could my two numb
kompoz [17]
Thought about it and theres a couple of others but i'm going to say 424-334
7 0
3 years ago
Is 5 a solution of the equation? 13 - d = 8
crimeas [40]
Yes because 13-5=8. not any other single number can be identified in the missing number
3 0
2 years ago
Read 2 more answers
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