Which of these sets of ordered pairs would define a line with a negative slope?

Mathematics

2 answers:

grin007 [14]3 years ago

7 0

Answer:

Step-by-step explanation:

Formula for finding slope with no graph: <u>y2 - y1</u>

x2 - x1

Now substitute each of the coordinates to its corresponding variables.

Remember: (x, y)

tatiyna3 years ago

7 0

Answer:

C (3, 6) and (5, 1)

Step-by-step explanation:

I just took the test and its right, also if you follow the steps on how to solve these, you will get your answer.

The steps are

y2 - y1

x2 - x1

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Need help with number 5

tangare [24]

Answer:

(3) y = 4x

Step-by-step explanation:

In order for the equation not to change, the point (0, 0) must be on the original line and so on the line after dilation. The only equation with (0, 0) as a point on the line is y=4x.

Dilation about the origin moves all points away from the origin some multiple of their distance from the origin. If a point is on the origin, it doesn't move. We call that point the "invariant" point of the transformation. For the equation of the line not to change, the invariant point must be on the line to start with.

8 0

3 years ago

The midpoint of CD is M(-1,-2). One endpoint is C (-9,-4). Find the coordinates of the other endpoint D.

yan [13]

$\bf ~~~~~~~~~~~~\textit{middle point of 2 points }\\\\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
% (a,b)
&C&(~ -9 &,& -4~) 
% (c,d)
&D&(~ x &,& y~)
\end{array}\qquad
% coordinates of midpoint 
\left(\cfrac{ x_2 + x_1}{2}\quad ,\quad \cfrac{ y_2 + y_1}{2} \right)
\\\\\\
\left( \cfrac{x-9}{2}~~,~~\cfrac{y-4}{2} \right)=\stackrel{midpoint~M}{(-1~~,~~-2)}\implies 
\begin{cases}
\cfrac{x-9}{2}=-1\\\\
x-9=-2\\
\boxed{x=7}\\
----------\\
\cfrac{y-4}{2}=-2\\\\
y-4=-4\\
\boxed{y=0}
\end{cases}$