D
because
A and B merely reflects the polygon on the graph
C merely translates the polygon
To cause a different area a graph usually must have a stretch or shrink and is indicated by multiplying either the x or y value. In this case both the x and y are being multiplied.
I just know the answer is 28
Answer:
Horizontal stretch by a factor of ½.
Step-by-step explanation:
We were given the parent function as:
![y = \sqrt[3]{0.5x}](https://tex.z-dn.net/?f=y%20%3D%20%20%5Csqrt%5B3%5D%7B0.5x%7D%20)
This was transformed to:
![y = \sqrt[3]{x}](https://tex.z-dn.net/?f=y%20%3D%20%20%5Csqrt%5B3%5D%7Bx%7D%20)
Let
![g(x) = \sqrt[3]{0.5x}](https://tex.z-dn.net/?f=g%28x%29%20%3D%20%20%5Csqrt%5B3%5D%7B0.5x%7D%20)
and
![f(x) = \sqrt[3]{x}](https://tex.z-dn.net/?f=f%28x%29%20%3D%20%20%5Csqrt%5B3%5D%7Bx%7D%20)
Then:

Hence the parent function has been stretched horizontally by a factor of 1/2 to obtain the transformed function.